我已经看过几个关于Tortoise和Hare Race的问题，但它们都与applet有关，我不是在编写applet。该程序意味着我的程序显示输出有问题。我想让程序显示如下所示的输出：
______T__________H________________________________
__________T_______________________H_______________
_____________T________H___________________________
等。直到乌龟或野兔到达终点并赢得比赛。截至目前，我的输出如下：
______________________________HT__________________________________________________HT__________________________________________________HT_
一遍又一遍似乎是一个无限循环。这是我的代码：
public class TortoiseAndHair {
public static void main ( String [] args )
{
int t = 0; // Keeps track of tortoise progress
int h = 0; // Keeps track of hare progress
System.out.println( "AND THEY'RE OFF!!" );
while (t < 50 || h < 50)
{
hareMove( h );
tortoiseMove( t );
if (t>1 && h> 1 && t == h) // Display when tortoise and hare occupy same space beyond start
{
System.out.print( "OUCH!!");
}
if ( t < 1 )
{ // Prevents tortoise from slipping behind start
t = 1;
}
if ( h < 1 )
{ // Prevents hare from slipping behind start
h = 1;
}
if ( t > 50 )
{ // Prevents tortoise from going passed finish line
t = 50;
}
if ( h > 50 )
{ // Prevents hare from going passed finish line
h = 50;
}
for ( int count = 1; count <= 50; count++)
{
System.out.print( "_" );
if ( count == h )
{
System.out.print( "H" );
}
if ( count == t )
{
System.out.print( "T" );
}
}
if (h < 50 && t == 50)
{ //Output if tortoise wins
System.out.print( "TORTOISE WINS!!" );
}
if ( t < 50 && h == 50)
{ // Output if hare wins
System.out.print( "HARE WINS!!" );
}
if ( h == 50 && t == 50)
{
System.out.print( "IT'S A TIE!!" );
}
}
}
/**
* This method will calculate the random integer that will dictate the tortoise's movements on the board,
* use that random integer to determine the tortoise's movements (tMove), and add that to the counter keeping track
* of the tortoise's position
* @param t is an int variable that is keeping track of the tortoises position on the board
* @return the tortoise's current position on the board after that turn
* Pre-Conditions: n is an int between 1 and 10, t is a positive int greater than 0 and less than 50
*/
public static int tortoiseMove (int t)
{
int n;
int tMove = 0;
n = (int) ( 10 * Math.random() ) + 1; // Generates random number between 1 and 10
if ( n > 10 )
{ // ensures n doesn't go higher than 10
n = 10;
}
// Series of if/else statements to control tMove
if ( n >= 1 && n <= 5)
{ // Fast plod if n is between 1 and 5
tMove = 3;
}
else
{
if ( n >= 6 && n <= 8)
{ // Slow Plod if n is between 6 and 8
tMove = 1;
}
else
{
if ( n == 9 || n == 10 )
{ // Slip if n is 9 or 10
tMove = -6;
}
}
}
// Add determined movement to tortoise counter and return that value
t += tMove;
return t;
}
/**
* This method will calculate the random integer that will dictate the hare's movements on the board,
* use that random integer to determine the hare's movements (hMove), and add that to the counter keeping track
* of the hare's position on the board
* @param h is an int variable keeping track of the hare's current position on the board
* @return the hare's position on the board after current turn
* Pre-Condition: n is an int between 1 and 10, h is a positive int greater than 0 and less than 50
*/
public static int hareMove (int h)
{
int n;
int hMove = 0;
n = (int) ( 10 * Math.random() ) + 1; // Generates random number between 1 and 10
if ( n > 10 )
{ // ensures n doesn't go higher than 10
n = 10;
}
//Series of if/else statements to control hMove
if ( n == 1 || n == 2 )
{ // Big hop if n is 1 or 2
hMove = 9;
}
else
{
if ( n >= 3 && n <= 5)
{ // Small hop is n is between 3 and 5
hMove = 1;
}
else
{
if ( n == 6 )
{ // Big slip is n is 6
hMove = -12;
}
else
{
if ( n == 7 || n == 8 )
{ // Small slip if n is 7 or 8
hMove = -2;
}
else
{
if ( n == 9 || n == 10 )
{ // Hare falls asleep if n is 9 or 10
hMove = 0;
}
}
}
}
}
// Add determined movement to hare counter and return value of h
h += hMove;
return h;
}
}
答案 0 :(得分：0)
移动后你永远不会重新分配h和t
h = hareMove( h );
t = tortoiseMove( t );
原语按值传递，因此您对移动方法中的h和t所做的任何更改都不会反映在原始值中。