我有一个数据库,可以根据标签确定不同的值。 标签确定其是否为豁免值。 例如,2 =非豁免,3 =豁免。如果我运行查询,我的结果看起来像这样
SELECT NAME, EXEMPTIONSTATUS
SUM(TOTAL_VALUE) AS 'TOTAL VALUE'
FROM ORDER_ACCOUNT JOIN ACCOUNT_INVOICE
WHERE ORDER_ACCOUNT.DATE BETWEEN 'M/D/YEAR' AND 'M/D/YEAR'
GROUP BY NAME, EXEMPTIONSTATUS
ORDER BY NAME ASC
我的查询
|Name |NON EXEMPT VALUE|EXEMPT VALUE|
|X |100 |200 |
如何让我的查询为值创建新列,例如:
self.tableView.cellLayoutMarginsFollowReadableWidth=NO;
我只是不知道如何对它进行排序,无论它是否在我的Where子句中。
答案 0 :(得分:0)
在SUM中使用CASE语句仅总计非EXEMPT,然后是EXEMPT,并将它们选为单独的列。与以下内容类似(可能需要将TOTAL_VALUE添加到GROUP BY,或删除EXEMPTIONSTATUS)
SELECT
NAME
,SUM(CASE WHEN EXEMPTIONSTATUS = 2 THEN TOTAL_VALUE ELSE 0 END) AS 'NON EXEMPT VALUE'
,SUM(CASE WHEN EXEMPTIONSTATUS = 3 THEN TOTAL_VALUE ELSE 0 END) AS 'EXEMPT VALUE'
FROM ORDER_ACCOUNT JOIN ACCOUNT_INVOICE
WHERE ORDER_ACCOUNT.DATE BETWEEN 'M/D/YEAR' AND 'M/D/YEAR'
GROUP BY NAME, EXEMPTIONSTATUS
ORDER BY NAME ASC
编辑:下面的新代码会在现有表格中添加新列。你需要用你的桌子替换#Test
,但我相信这会让你得到你想要的东西。
SELECT
NAME,
EXEMPTIONSTATUS
,[TOTAL_VALUE]
,(SELECT SUM(CASE WHEN EXEMPTIONSTATUS = 2 THEN TOTAL_VALUE ELSE 0 END) FROM #Test t WHERE t.NAME = NAME) 'NON EXEMPT VALUE'
,(SELECT SUM(CASE WHEN EXEMPTIONSTATUS = 3 THEN TOTAL_VALUE ELSE 0 END) FROM #Test t WHERE t.NAME = NAME) 'EXEMPT VALUE'
FROM #Test
这给了我以下输出
| NAME | EXEMPTIONSTATUS | TOTAL_VALUE | NON EXEMPT VALUE | EXEMPT VALUE |
| X | 2 | 100 | 100 | 200 |
| X | 3 | 200 | 100 | 200 |
答案 1 :(得分:0)
让我们说你的表结构是这样的:
CREATE TABLE tab(ID int, Name nvarchar(20), ExemptionStatus int, TotalValue int);
INSERT INTO tab(ID, Name, ExemptionStatus, TotalValue) values (1, 'X', 2, 100);
INSERT INTO tab(ID, Name, ExemptionStatus, TotalValue) values (2, 'X', 3, 200);
所以你的数据是这样的:
ID Name ExemptionStatus TotalValue
1 X 2 100
2 X 3 200
然后您使用的查询是:
SELECT NotExempted.Name,
NotExempted.NonExemptValue,
Exempted.ExemptValue
FROM (SELECT Name,
CASE
WHEN ExemptionStatus = 2 THEN TotalValue
END
AS 'NonExemptValue'
FROM #tab
) NotExempted
INNER JOIN (SELECT Name,
CASE
WHEN ExemptionStatus = 3 THEN TotalValue
END
AS 'ExemptValue'
FROM #tab
) Exempted ON NotExempted.Name = Exempted.Name
WHERE NotExempted.NonExemptValue IS NOT NULL
AND Exempted.ExemptValue IS NOT NULL
GROUP BY NotExempted.Name,
NotExempted.NonExemptValue,
Exempted.ExemptValue
您的结果将如下所示:
Name NonExemptValue ExemptValue
X 100 200
你可以在这里看到 - > http://sqlfiddle.com/#!9/8902d3/2
现在,让我们说你有这样的数据:
CREATE TABLE #tab(ID int, Name nvarchar(20), ExemptionStatus int, TotalValue int)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (1, 'X', 2, 100)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (2, 'X', 3, 200)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (3, 'X', 2, 1000)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (4, 'X', 3, 2000)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (5, 'X', 2, 1045)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (6, 'X', 3, 2045)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (7, 'X', 2, 1034)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (8, 'X', 3, 2023)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (9, 'X', 2, 1023)
INSERT INTO #tab(ID, Name, ExemptionStatus, TotalValue) values (10, 'X', 3, 2076)
看起来像这样:
ID Name ExemptionStatus TotalValue
1 X 2 100
2 X 3 200
3 X 2 1000
4 X 3 2000
5 X 2 1045
6 X 3 2045
7 X 2 1034
8 X 3 2023
9 X 2 1023
10 X 3 2076
如果您需要将总值相加,那么您可以使用以下查询(这是对上述查询的略微修改):
SELECT NotExempted.Name,
NotExempted.NonExemptValue,
Exempted.ExemptValue
FROM (SELECT Name,
CASE
WHEN ExemptionStatus = 2 THEN (SELECT SUM(TotalValue) FROM #tab WHERE ExemptionStatus = 2)
END
AS 'NonExemptValue'
FROM #tab
) NotExempted
INNER JOIN (SELECT Name,
CASE
WHEN ExemptionStatus = 3 THEN (SELECT SUM(TotalValue) FROM #tab WHERE ExemptionStatus = 3)
END
AS 'ExemptValue'
FROM #tab
) Exempted ON NotExempted.Name = Exempted.Name
WHERE NotExempted.NonExemptValue IS NOT NULL
AND Exempted.ExemptValue IS NOT NULL
GROUP BY NotExempted.Name,
NotExempted.NonExemptValue,
Exempted.ExemptValue
您的结果将如下所示:
Name NonExemptValue ExemptValue
X 4202 8344
你可以在这里看到 - > http://sqlfiddle.com/#!9/02c76/3
希望这有帮助!!!