我刚接触编码，目前正在上线。现在我被卡住了，我无法找到任何帮助我继续前进的事情。任务是随机打印给予程序的数量。输入5，程序为您提供5个随机数。之后将它们排成奇数和偶数。这一切都很好。
我的问题是我不知道如何计算每个数组中的数字（不将它们加在一起），而是计算有多少奇数以及有多少偶数。
寻求帮助和指导。
抱歉，如果有答案，请在询问之前尽力找到答案。 d.s
import java.util.*;
public class RandomNbrs {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println("How many random numbers do you want? (0-999)");
int numb = scan.nextInt();
System.out.println("Your random numbers:");
int array[] = new int[numb];
for(int i =0; i < numb; i++){
array [i] = (int) (0 + 1000 * Math.random());
System.out.print(array[i]);
System.out.print(" ");
}
System.out.println();
System.out.println();
System.out.println("Even numbers: ");
for(int j =0; j < numb; j++){
if(array[j] %2 == 0){
System.out.print(array[j]);
System.out.print(" ");
}
}
System.out.println();
System.out.println();
System.out.println("Odd numbers: ");
int oddNbr = 0;
for(int k =0; k < numb; k++){
if(array[k] %2 == 1){
System.out.print(array[k]);
System.out.print(" ");
}
}
}
}
答案 0 :(得分：0)
您可能误解了一些概念。
因此，如果您确实需要两个不同的数组用于这两个数字，则需要再创建两个数组。 有几种方法，但这将是您的代码最简单的（可能不一定是最好的）：
import java.util.*;
public class RandomNbrs
{public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
System.out.println("How many random numbers do you want? (0-999)");
int numb = scan.nextInt();
System.out.println("Your random numbers:");
int array[] = new int[numb];
int temp,countOdd=0,countEven=0;
for(int i =0; i < numb; i++){
//I am storing the random generated number in a temporary variable
//Then i check if it is odd or even and increase the count by using a counter
temp= (int) (0 + 1000 * Math.random());
if (temp%2 == 0):
countEven++;
else
countOdd++;
array[i]=temp
System.out.print(array[i]);
System.out.print(" ");
}
System.out.println();
System.out.println();
//Here i am creating two new arrays as you specified.
//if you just want to print the odd and even numbers AND their couns, you dont necessarily need to make these two arrays.
int arrayOdd[] = new int[countOdd];
int arrayEven[]=new int[countEven];
//Counter for accessing the elements of the two new arrays
int counter1=0,counter2=0;
//Filling the two new arrays with odd and even numbers from the prev array
for(int j =0; j < numb; j++){
if(array[j] %2 == 0){
arrayEven[counter1++]=array[j];
}
else
arrayOdd[counter2++]=array[j];
}
//Print odd
System.out.println("Odd:");
for(int k =0; k < countOdd; k++){
System.out.print(arrayOdd[k]);
System.out.print(" ");
}
System.out.println("Total odd numbers="+countOdd);
//or arrayOdd.length() also gives the count.
//Similar for printing even numbers
}}
此外，您还可以使用ArrayList，您可以动态地直接在2个数组中存储奇数甚至生成的随机数，而不需要第三个公共数组。如果您想知道如何使用这个，请与我们联系。 ：）
答案 1 :(得分：0)
这就是我解决任务的方法：
public class testTest {
public static void main(String[] args) {
// TODO Auto-generated method stub
int oddCounter=0;
int evenCounter=0;
Scanner scan = new Scanner(System.in);
System.out.println("How many random numbers do you want? (0-999)");
int numb = scan.nextInt();
System.out.println("Your random numbers:");
int array[] = new int[numb];
for(int i =0; i < numb; i++){
array [i] = (int) (0 + 1000 * Math.random());
System.out.print(array[i]);
System.out.print(" ");
}
System.out.println();
System.out.println();
for(int j =0; j < numb; j++){
if(array[j] %2 == 0){
evenCounter++;
}
}
System.out.println("Dessa " + evenCounter + " Even numbers: ");
for(int j =0; j < numb; j++){
if(array[j] %2 == 0){
System.out.print(array[j]);
System.out.print(" ");
}
}
System.out.println();
System.out.println();
for(int k =0; k < numb; k++){
if(array[k] %2 == 1){
oddCounter++;
}
}
System.out.println("Dessa " + oddCounter + " Odd numbers: ");
for(int k =0; k < numb; k++){
if(array[k] %2 == 1){
System.out.print(array[k]);
System.out.print(" ");
}
}
}
}