Question

我有一个PHP文档，它会执行一些MySQL并回复它。

代码：
$query1 = "SELECT * FROM feed, recipients WHERE feed.title LIKE \"%recipients.suburb%"\ ORDER BY pubDate DESC";

recipients.suburb（table.column）在我的MySQL数据库中。如何在此处执行通配符？

这样可行，但我不能为表格做到这一点？

$query1 = "SELECT * FROM feed, recipients WHERE feed.title LIKE '%test%' ORDER BY pubDate DESC";

我想查看专栏feed.title，看看是否有recipients.suburb中的任何文字。这是一个脚本，最终将根据与用户所在位置相关的MySQL文本向用户发送电子邮件。

Answer 1

尝试：

SELECT * 
FROM feed, recipients 
WHERE feed.title LIKE concat('%', recipients.suburb, '%')
ORDER BY pubDate DESC

Answer 2

如果你有一个带有id的suburb表，你会有更好的E-R设计。然后，您可以在suburb_id表和feed表中使用外键recipients。这会在您要查找的feed和recipient之间创建多对多关系。

然后解决方案是使用联接将收件人与郊区相同的订阅源匹配。

以下是我的建议：

CREATE TABLE IF NOT EXISTS `feed` (
  `feed_id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
  `title` varchar(100) DEFAULT NULL,
  `suburb` BIGINT( 20 ) UNSIGNED NULL,
  `pubDate` date DEFAULT NULL,
  PRIMARY KEY (`feed_id`)
  UNIQUE KEY `feed_id` (`feed_id`)
);

CREATE TABLE IF NOT EXISTS `recipients` (
  `recipient_id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(100) NOT NULL,
  `suburb` bigint(20) unsigned DEFAULT NULL,
  PRIMARY KEY (`recipient_id`),
  UNIQUE KEY `recipient_id` (`recipient_id`)
);

CREATE TABLE IF NOT EXISTS `suburb` (
  `suburb_id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(100) NOT NULL,
  PRIMARY KEY (`suburb_id`),
  UNIQUE KEY `suburb_id` (`suburb_id`)
);

并使用此SELECT语句：

SELECT feed.title, recipients.name, suburb.name
FROM feed, recipients, suburb
WHERE feed.suburb = suburb.suburb_id
AND suburb.suburb_id = recipients.suburb
AND feed.title LIKE CONCAT(  '%', suburb.name,  '%' ) 
ORDER BY pubDate DESC

MySQL LIKE表的通配符

2 个答案: