我正在使用改装。要捕获响应，我正在使用拦截器：
OkHttpClient okHttpClient = new OkHttpClient();
okHttpClient.interceptors().add(myinterceptor);
这里是拦截器代码：
new Interceptor() {
@Override
public Response intercept(Chain chain) throws IOException {
Request request = chain.request();
Response response = chain.proceed(request);
if (path.equals("/user")){
String stringJson = response.body().string();
JSONObject jsonObject = new JSONObject(stringJson);
jsonObject.put("key",1);
//here I need to set this new json to response and then return this response
如何在OkHttp响应中更改正文？
答案 0 :(得分：28)
添加此
MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject);
return response.newBuilder().body(body).build();
在您的回复修改后。 jsonObject是您要返回的已修改JSON。
答案 1 :(得分：7)
下面是Response Intercepter类，您可以在其中拦截okkhttp响应并添加您自己的响应。并将其发送给改造。
import org.json.JSONException;
import org.json.JSONObject;
import java.io.IOException;
import okhttp3.Interceptor;
import okhttp3.MediaType;
import okhttp3.Request;
import okhttp3.ResponseBody;
import retrofit2.Response;
public class ApiResponseInterceptor implements Interceptor {
@Override
public okhttp3.Response intercept(Chain chain) throws IOException {
Request request = chain.request();
okhttp3.Response response = chain.proceed(request);
if(response.code() == 200) {
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("code",200);
jsonObject.put("status","OK");
jsonObject.put("message","Successful");
MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject.toString());
return response.newBuilder().body(body).build();
} catch (JSONException e) {
e.printStackTrace();
}
} else if(response.code() == 403) {
}
return response;
}
}
您将在改装回调中获得修改后的回复
call.enqueue(new Callback<EventResponce>() {
@Override
public void onResponse(Call<EventResponce> call, Response<EventResponce> response) {
// you will get your own modified responce here
}
@Override
public void onFailure(Call<EventResponce> call, Throwable t) {
}
});
答案 2 :(得分：4)
作为一个小改动，我不会使用string()方法，因为它只能在此请求上调用一次。您确实使用了response.newBuilder()，因此链中的其他拦截器将能够在您的新链接上调用string()，但我发现自己浪费了几个小时，因为我实际上是在调用它两次：P。
所以我建议如下
BufferedSource source = response.body().source();
source.request(Long.MAX_VALUE); // Buffer the entire body.
Buffer buffer = source.buffer();
String responseBodyString = buffer.clone().readString(Charset.forName("UTF-8"));
答案 3 :(得分：0)
JSONObject postdata = new JSONObject();
try {
postdata.put("citizenId", "2222222222222");
postdata.put("accuracy", 3043.323);
postdata.put("provider", "wifi");
postdata.put("gpsTime", 1111111111111L);
postdata.put("lat", 23434.564);
postdata.put("lng", 34343.5445);
postdata.put("appId", "201");
} catch(JSONException e){
// TODO Auto-generated catch block
e.printStackTrace();
}
RequestBody body = RequestBody.create(MEDIA_TYPE,postdata.toString());
HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
interceptor.setLevel(HttpLoggingInterceptor.Level.BODY);
final OkHttpClient client = new OkHttpClient.Builder().addInterceptor(interceptor).build();
// final OkHttpClient client = new OkHttpClient.Builder().addInterceptor(interceptor).build();
final Request request = new Request.Builder()
.url(base_url)
.post(body)
.addHeader("Content-Type", "application/json")
.addHeader("Authorization", "JWT eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJvd25lcklkIjoyLCJvd25lclR5cGUiOiJMRUFERVIiLCJpYXQiOjE1MDE4Mjc4MDMsImV4cCI6MzMwMzc4Mjc4MDMsImF1ZCI6InNlbmRpdC5hc2lhIiwiaXNzIjoic2VsZiJ9.3Gpn3beZfdYsMOLTjksLwmxyfbrfqiojdm1n-gh6CXY")
.addHeader("cache-control", "no-cache")
.build();
client.newCall(request).enqueue(new Callback() {
@SuppressLint("LongLogTag")
@Override
public void onResponse(Call call, Response response) throws IOException {
try {
// response = client.newCall(request).execute();
// Protocol protocol = response.protocol();
// assertEquals(Protocol.HTTP_1_1, protocol);
// BufferedSource source = response.body().source();
// source.request(Long.MAX_VALUE); // Buffer the entire body.
// Buffer buffer = source.buffer();
// String responseBodyString = buffer.clone().readString(Charset.forName("UTF-8"));
if(response.code() == 200) {
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("code",200);
jsonObject.put("status","OK");
jsonObject.put("message","Successful");
MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject.toString());
BufferedSource source = response.body().source();
source.request(Long.MAX_VALUE); // Buffer the entire body.
Buffer buffer = source.buffer();
String responseBodyString = buffer.clone().readString(Charset.forName("UTF-8"));
Log.e("response body responseBodyString ", body.string());
Log.e("response body responseBodyString ", responseBodyString);
} catch (JSONException e) {
e.printStackTrace();
}
Log.e("response", String.valueOf(response));
Log.e("response body", String.valueOf(response.body()));
} }catch (IOException e) {
e.printStackTrace();
}
}
@Override
public void onFailure(Call call, IOException e) {
Log.e("response onFailure ", String.valueOf(e));
}
});
答案 4 :(得分：0)
这是一个紧密完整的示例，其中添加了一个将JSON修改为OkHttpClient的拦截器。它使用GSON来管理JSON。
client.addInterceptor(chain -> {
final Request request = chain.request();
final String path = request.url().uri().getPath();
final Response response = chain.proceed(request);
String body = response.body().string();
final JsonElement element = new JsonParser().parse(body);
if ("/the/endpoint/you/want/to/modify".equals(path)){
final JsonObject object = element.getAsJsonObject();
// v v v v v v All this for these lines v v v v v v v
object.addProperty("some_json_name","some_json_value");
object.addProperty("existing_property","updated_value");
object.addProperty("numbers_work_too",1.2);
// ^ ^ ^ ^ ^ ^ All this for these lines ^ ^ ^ ^ ^ ^ ^
body = object.toString();
}
return response.newBuilder().body(ResponseBody.create(response.body().contentType(), body)).build();
});