请我选择用户的共同朋友,$my_id
是$_SESSION['user'];
而$user_id
是所选用户。这是代码:
<?php
include 'connect.php';
include 'functions.php';
$my_frnds = mysqli_query{$con, "SELECT * FROM friends WHERE one='$my_id' OR two='$my_id'"};
while($my_friends = mysqli_fetch_array($my_frnds)){
$one = $my_friends['one'];
$two = $my_friends['two'];
if($one == $my_id){
$user == $two;
} else
$user == $one;
}
$user_frnds = mysqli_query{$con, "SELECT * FROM friends WHERE one='$user_id' OR two='$user_id'"};
while($user_friends = mysqli_fetch_array($user_frnds)){
$user_one = $user_friends['one'];
$user_two = $user_friends['two'];
if($user_one == $my_id){
$users == $user_two;
} else
$users == $user_one;
}
?>
假设我的朋友是(1,2,3,4,5,6,7),而用户朋友是(2,4,6,7,8,9,10),所以共同的朋友是( 2,4,6,7)我的问题是如何让共同的朋友出来并回应他们的ids?对不起,我犯了一个错误,这是原始编码
答案 0 :(得分:1)
如果一个是你的id,两个是朋友id:
select * from friends
inner join (select * from friends where one = $user_id) as temp on temp.two = friends.two
where friends.one = $my_id
答案 1 :(得分:0)
SELECT * FROM friends AS f1
INNER JOIN
(SELECT * FROM friends WHERE one = $user_id OR two = $user_id) AS f2
ON (f1.one = f2.one OR f1.one = f2.two)
WHERE f1.one = $my_id OR f1.two = $my_id
希望这会有所帮助。