freq.txt
>FREQ //74
4.163186002791e+04 3.578830331359e+04 3.076496349687e+04 2.644671278966e+04 2.273458304119e+04
1.954349752908e+04 1.680032112209e+04 1.444218412726e+04 1.241504140604e+04 1.067243373686e+04
9.174423035938e+03 7.886677033340e+03 6.779682426302e+03 5.828068476394e+03 5.010025548360e+03
1.737988920100e+03 1.284332855871e+03 1.104060538508e+03 8.158747205330e+02 7.013564117662e+02
6.029121922103e+02 5.182858606802e+02 4.455379022877e+02 2.433020871700e+02 2.091515701348e+02
1.797945089525e+02 1.545580816278e+02 1.328639052196e+02 9.818329499070e+01 7.255514128762e+01
5.361653963401e+01 4.609078195788e+01 3.962135930423e+01 3.406000172766e+01 2.927925083995e+01
2.516953864546e+01 2.163667639887e+01 1.859969593339e+01 1.598899398582e+01 1.374473698894e+01
1.181548977143e+01 1.015703673713e+01 8.731368506527e+00 7.505810795983e+00 6.452275569743e+00
5.546617302183e+00 4.768079596776e+00 4.098819479081e+00 3.523498461194e+00 3.028931005477e+00
2.603782330822e+00 2.238308635635e+00 1.924133783786e+00 1.654057335509e+00 1.421889523591e+00
1.222309392724e+00 1.050742850800e+00 9.032578372386e-01 7.764742057598e-01 6.674862562538e-01
5.737961402745e-01 4.932566139141e-01 3.133421372728e-01 2.315524554696e-01 1.990511474577e-01
1.711118080085e-01 1.470941072881e-01 1.264475938317e-01 1.086990789815e-01 9.344179207682e-02
8.032605785014e-02 6.905128236880e-02 5.935906385039e-02 5.102727046220e-02
我的代码
program lk
implicit none
integer :: i
real,dimension(74) :: fr
open(10,file='freq.txt')
read(10,*)
do i=1,74
read(10,*)fr(i)
end do
end program
t line 11 of file lk.f90 (unit = 10, file = 'freq.txt')
Fortran runtime error: End of file
问题是什么?我应该如何设置正确的格式?
答案 0 :(得分:1)
好的,答案可以放大我先前的评论。
从文件读取的每个格式化read
语句都从一行的开头开始。或者,如果您愿意,每个此类read
语句都在行尾结束。这里代码试图从少于74行的文件中读取74行,即运行时对象。
一种解决方案是使用现代Fortran的功能来读取多个元素。在一个简单的例子中,例如在一个语句read(10,*) fr
中读取整个数组就足够了。 *
格式表示 list-directed 输入,所有现代编译器(据我所知)将完成所有必要的驴工作,以获得74个实数来填充{{1超出那个档案。