Question

我正在尝试比较在我的第一个函数中检索到的两个字符串值，但它不起作用。它一直告诉我“语法无效”并将光标移动到elif行。

这是我的计划......

def find_number_of_service():
    with open('TheData.txt', 'r') as data_file:
        data = data_file.read()

    countS = data.count('S')
    countW = data.count('W')

    print ("There are " + str(countS) + " S's")
    print ("There are " + str(countW) + " W's")
    return


def find_popular_service():
    if (countS) > (countW):
        print ("The most used service to buy tickets was the school.")
        elif print ("The most used service to buy tickets was the website.")

        return

#Main program
find_number_of_service()
find_popular_service()

提前谢谢。

Answer 1

您没有给elif条件。 elif表示otherwise if...。也许你的意思是else。
elif应与if
print ...应该换行。

Answer 2

您未正确定义的第二个函数elif中的问题应该是elif <condition>:

这里是工作函数

def find_popular_service():
    if (countS) > (countW):
        print ("The most used service to buy tickets was the school.")
    else:
        print ("The most used service to buy tickets was the website.")
    return

比较2个字符串值，不工作！？

2 个答案: