Question

我正在尝试打开一个包含两个句子的文件，并将这两个句子分成一个单词列表。但是，当我这样做时，我还得到一个额外的空列表，如何防止这种情况？

branch1

我明白了：

master

Answer 1

使用splitlines()将文件的所有行读入列表：

with open('filename.txt', 'r') as f:
    mylist = f.read().splitlines()

使用此列表理解拆分行：

mylist = [line.split() for line in mylist]

使用filter()删除所有空列表项：

mylist = filter(None, mylist)

您还可以在阅读文件时完成所有这些操作：

mylist = []
with open('filename.txt', 'r') as f:
    for line in f:
        if line.strip():
            mylist.append(line.split())

Answer 2

x1=[]
fopen=open("testxxx",'r')
for line in fopen:
   x=line.split()
   if x:
       x1.append(x)
print x1

Answer 3

删除空列表：

x1= [x for x in x1 if x]

Answer 4

您可以使用readlines：

with open('filename.txt', 'r') as f:
    mylist = [line for line in f.readlines() if line.strip() != '']

或者：

with open('filename.txt', 'r') as f:
    lines = []
    for line in f.readlines():
        if line.strip() != '':
            lines.append(line)

或者：

with open('filename.txt', 'r') as f:
    lines = filter(lambda x: x.strip() != '', f.readlines())

Answer 5

您可以在尝试拆分其单词时检查读取行是否为空。

word_list = []
lines = []

with open('myfile.txt') as file:
    # stripping the whitespaces as the blank line may contain whitespaces
    lines = [line.strip() for line in file.readlines()]

# split to words those lines that are not empty strings
word_list = [line.split() for line in lines if line]

或者，带有单行

with open('myfile.txt') as file:
    word_list = [line.split() for line in file.readlines() if line.strip()]

请注意，空字符串''在python中是假的。因此，如果line是空字符串，if line的结果为{0}，同样适用于line.strip()。看一下python中的truth-value-testing。

从文件Python分割行时删除一个额外的空列表

5 个答案:

或者，带有单行