使用以下XML
(i:Int)
我希望得到ID = XYZ-987条件名=" task1",value =" abc" AND name =" task2",value =" efg" AND name =" task5",value =" nop"
我得到2个结果(ABC-123和XYZ-987)而不是1个(XYZ-987)。 使用以下XPATH表达式
<node1>
<node2>
<node3>
<id>ABC-123</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task3" operation="and" value="hij" />
<task name="task4" operation="or" value="klm" />
<task name="task5" operation="and" value="nop" />
<task name="task6" value="uvw" />
</condition>
</node3>
<node3>
<id>XYZ-987</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task5" operation="and" value="nop" />
</condition>
</node3>
<node3>
<id>RST-567</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task8" operation="and" value="jkl" />
<task name="task9" operation="and" value="rst" />
<task name="task10" value="xyz" />
</condition>
</node3>
<node3>
<id>PQR-345</id>
<condition>
<task name="task1" operation="and" value="ijk" />
<task name="task2" operation="and" value="klm" />
<task name="task8" operation="and" value="jkl" />
<task name="task9" operation="and" value="rst" />
</condition>
</node3>
</node2>
</node1>
如何根据输入条件大小过滤这2个结果,并按照上述3个条件获取条目?
参考XPATH executing complex queries来发展表达。
答案 0 :(得分:1)
通过在表达式中附加“and count(condition / task)= 3”得到答案。
/node1/node2/node3[condition/task[@name='task1' and @value='abc'] and condition/task[@name='task2' and @value='efg'] and condition/task[@name='task5' and @value='nop'] and count(condition/task)=3]/id