Question

我使用以下命令启动netty jax rs服务器：

    NettyJaxrsServer netty = new NettyJaxrsServer();
    netty.setHostname(HOST);
    netty.setPort(port);        
    netty.setDeployment(resteasyDeployment);        

    // Some optional extra configuration
    netty.setKeepAlive(true);
    netty.setRootResourcePath("/");
    netty.setSecurityDomain(null);
    netty.setIoWorkerCount(16);
    netty.setExecutorThreadCount(16);

    LOGGER.info("Starting REST server on " + System.getenv("HOSTNAME"));        
    // Start the server
    //("Starting REST server on " + System.getenv("HOSTNAME")); 
    netty.start();  
    LOGGER.info("Started!");

这很好但是没有办法检查服务器是否实际启动并且可以接受REST请求。我一直在使用REST接口的try / catch请求，如果我得到异常，则在catch块中等待，然后重试。它有效，但有点乱：

private void bringUpInterface(SlaveRestInterface slaveAgent, Target localTarget) {
    LOGGER.info("Bringing up interface on " + localTarget.getHostName());
    Response r = null;
    long startTime = System.currentTimeMillis();
    boolean isReady = false;
    long wait = 50;
    int count = 0;
    try {
        while (!isReady) {
            try {
                r = slaveAgent.ping();
                r.close();
                isReady = true;
                long endTime = System.currentTimeMillis();
                SYS_LOGGER.info(" [OK]" + " (" + (endTime - startTime + "ms") + ")");

            } catch (ProcessingException ce) {
                if(r != null) {
                    r.close();
                }

                if (count == DEFAULT_TIMEOUT_SEC) {
                    throw new TimeoutException("Failed to start REST interface in " + DEFAULT_TIMEOUT_SEC
                            + "second(s)");
                }
                Thread.sleep(wait);
                wait *= 2;
                count++;
            } catch (Exception e) {
                isReady = false;
                throw new FatalException("Couldn't connect to REST interface on " + localTarget.getHostName());
            }
        }
    } catch (InterruptedException | TimeoutException ie) {
        isReady = false;
        throw new FatalException("REST interface did not come up on "  + localTarget.getHostName());
    }
}

我想知道我是否可以覆盖start（）方法，并添加代码来ping端点，可能使用HttpRequest。似乎没有任何编程方式来查看服务器是否已启动。

Answer 1

如果你可以加入Netty，请带上你的#include <iostream> #include <vector> #include <algorithm> using namespace std; enum class EventType {ARRIVE, LEAVE}; struct Event{ int time; EventType type; Event(){} Event(int tm, EventType t) : time(tm), type (t){} // inline bool operator<(const Event& e) const {return time < e.time || (time == e.time && type==EventType::LEAVE);} }; bool eventCompare(const Event& e1, const Event& e2) { if(e1.time < e2.time){ return true; } else if(e1.time == e2.time) { if(e1.type == EventType::LEAVE && e2.type == EventType::ARRIVE) { return true; } else { return false; } } else { return false; } } int main() { int visits; int timeStart, timeEnd; int maxVisits, maxDuration, localMaxVisits, localStartTime, localEndTime, duration; std::vector<Event> events; std::vector<Event>::const_iterator it; // Get each Case from stdin. // 0 is the special stopping case. while(cin>>visits && visits!=0) { events.clear(); // Read all the visits, for each one save two entries to the visits-vector, // one for the arrival time another for the leaving time. for(int i=1; i<=visits; ++i){ cin>>timeStart>>timeEnd; Event eStart(timeStart, EventType::ARRIVE); Event eEnd(timeEnd, EventType::LEAVE); events.push_back(eStart); events.push_back(eEnd); } // Sorting the vector so that events are ordered by their arrival time. // In case two events coincide on arrival time, we place leaving events before arrival events. std::sort(events.begin(), events.end(), eventCompare); maxVisits=0; maxDuration=0; localMaxVisits=0; localStartTime=0; localEndTime=0; // Loop through the sorted vector for(it=events.begin(); it!=events.end(); ++it){ // If the event type is arrival if((*it).type == EventType::ARRIVE) { // We only reset the localStartTime if there is no // gap between the last endtime and the current start time // For example two events 11-13 and 13-15 should be treated as one long event // with duration 11-15 if(localEndTime < (*it).time) { localStartTime = (*it).time; } localMaxVisits++; } else { // Event type leave // Calculate the duration duration = (*it).time - localStartTime; // If we have a new max in overlaps or equal overlaps but larger duration than previous // We save as the global max. if(localMaxVisits > maxVisits || (localMaxVisits == maxVisits && duration>maxDuration)) { maxVisits=localMaxVisits; maxDuration = duration; } localMaxVisits--; localEndTime= (*it).time; } } cout<<maxVisits<<" "<<maxDuration<<endl; } return 0; }并执行以下操作：

ServerBootstrap

如何检查Netty Jax Rs服务器是否准备就绪

1 个答案: