我有一个名为git shortlog -s -n
的分支。现在我想知道每天发生了多少次提交（即每天）。
我想要Toal的提交次数（即）一天中的提交次数。
我尝试了这个命令，但是它提供了来自分支的所有提交计数
//
// notification.swift
// NSFetchController Pro
//
// Created by Mr.Geeker on 08/02/15.
// Copyright (c) 2015 X2coder. All rights reserved.
//
import UIKit
class notification {
func createNotification(#hour:String, day:String, msgBody:String)->Bool
{
if(self.checkifNotificationOnOrOff())
{
//println("\(araToString(hour))")
var dateFormatter:NSDateFormatter = NSDateFormatter()
dateFormatter.locale = NSLocale.currentLocale()
dateFormatter.dateStyle = NSDateFormatterStyle.NoStyle
dateFormatter.timeStyle = NSDateFormatterStyle.ShortStyle
var convertedTime:String = ""
var testDate:NSDate = NSDate()
var timeFormat:NSString = dateFormatter.stringFromDate(testDate)
// Get the range of date (AM OR PM )
var amRange:NSRange = timeFormat.rangeOfString(dateFormatter.AMSymbol)
var pmRange:NSRange = timeFormat.rangeOfString(dateFormatter.PMSymbol)
var is24h:Bool = (amRange.location == NSNotFound && pmRange.location == NSNotFound)
if is24h {
araToString(hour)
}else{
var dateFormatter2:NSDateFormatter = NSDateFormatter()
dateFormatter2.dateFormat = "HH:mm"
var hourDate:NSDate = dateFormatter2.dateFromString(hour)!
var pmAmDateString:NSString = dateFormatter2.stringFromDate(hourDate)
convertedTime = pmAmDateString
println(convertedTime)
}
var hourAndMiOnly:NSArray = convertedTime.componentsSeparatedByString(":")
var onlyHour:Int = 0
var onlyMinuts:Int = 0
for var i:Int = 0; i < 2; i++ {
for thimes in hourAndMiOnly
{
if i == 0
{
onlyMinuts = thimes.integerValue
}
if i == 1 {
// we should add -1 before the class
onlyHour = (thimes.integerValue)
if onlyHour < 1
{
onlyHour = 00
}
break
}
}
}
let DaysDic = [0:"None",1:"Sunday",2 :"Monday",3 :"Tuesday",4 :"Wednesday",5 :"Thursday",6 :"Friday",7 :"Saturday"]
var ConvertDayToInt:Int?{
for (key,value) in DaysDic
{
if value == day
{
return key
}
}
return nil
}
//println("Hour is \(onlyHour) And Minut \(onlyMinuts) AND Day \(ConvertDayToInt)")
let date = NSDate()
var userInfo: [NSObject : AnyObject]?
var createCalender:NSCalendar = NSCalendar(calendarIdentifier: NSGregorianCalendar)!
var dateComponenet:NSDateComponents = createCalender.components(NSCalendarUnit.YearCalendarUnit | NSCalendarUnit.WeekCalendarUnit, fromDate: date)
dateComponenet.weekday = ConvertDayToInt!
dateComponenet.hour = onlyHour
dateComponenet.minute = onlyMinuts
var fireDateToRun:NSDate = createCalender.dateFromComponents(dateComponenet)!
var notificationClass:UILocalNotification = UILocalNotification()
notificationClass.alertBody = msgBody
notificationClass.fireDate = fireDateToRun
notificationClass.soundName = UILocalNotificationDefaultSoundName
notificationClass.repeatInterval = NSCalendarUnit.WeekCalendarUnit
notificationClass.timeZone = NSTimeZone.defaultTimeZone()
notificationClass.applicationIconBadgeNumber = UIApplication.sharedApplication().applicationIconBadgeNumber + 1
UIApplication.sharedApplication().scheduledLocalNotifications = [notificationClass]
}else{
// call protocol function not support notification
}
return true
}
func araToString(numericString:String)->NSString
{
var nsMutString:NSMutableString = NSMutableString(string: numericString)
let ArabicString:NSString = "١٢٣٤٥٦٧٨٩:"
let EnglishString:NSString = "123456789:"
for ( var i:Int = 0 ; i < ArabicString.length ; i++)
{
var a:NSString = ArabicString.substringWithRange(NSMakeRange(i, 1))
var w:NSString = EnglishString.substringWithRange(NSMakeRange(i, 1))
nsMutString.replaceOccurrencesOfString(a, withString: w, options: NSStringCompareOptions.LiteralSearch, range:NSMakeRange(0, nsMutString.length))
}
return nsMutString
}
func deleteAll(){
let appnoti = UIApplication.sharedApplication()
let delArray = appnoti.scheduledLocalNotifications
if delArray.count > 0
{
appnoti.cancelAllLocalNotifications()
}
}
func checkifNotificationOnOrOff()->Bool
{
let systemVer:String = UIDevice.currentDevice().systemVersion
var finalFloat:Float = NSString(string: systemVer).floatValue
if finalFloat < 8 {
return false
}else{
return true
}
}
}
我的问题是计算一天中的提交次数
答案 0 :(得分：15)
这回答了＆＃34;每天＆＃34;你问的身份危机问题的一面，似乎无法确定它是否需要每天/每天＆＃34;暗示多天或只是＆＃34;一天＆＃34;暗示单身。显然，＆＃34;每天＆＃34;是一个＆＃34;一天＆＃34;的超集，所以这是一个有用的展示; grep这样可以做其余的事情。
短而甜蜜：
git log --date=short --pretty=format:%ad | sort | uniq -c
示例输出：
1 2017-12-08
6 2017-12-26
12 2018-01-01
13 2018-01-02
10 2018-01-14
7 2018-01-17
5 2018-01-18
说明：
git log是先决条件。--date=short将date-format设置为YYYY-MM-DD，其中（A）是我们所需要的，（B）随后按字母顺序sort按时间顺序排列。--pretty=format:%ad告诉git我们只想让每个提交a uthor d吃掉我们首选的date-format。如果你愿意，你可以使用cd来c省略d吃，但只要cherry-pick rebase | sort uniq等等。| uniq -c需要YYYY-MM-DD，因为它只检查相邻的重复项。当然，我们几乎肯定希望最后订购日期。to_double计算每个for col in cols10:
if col.startswith('m_'):
df[col] = df[col].astype(float)
的相邻重复项的数量，并预先计入日期。答案 1 :(得分：5)
试试这个：
$ git rev-list --count --since=<start-date> --before=<end-date> <ref>
例如，要获取当前分支中昨天完成的提交次数：
$ git rev-list --count --since=yesterday --before=today HEAD
也接受绝对日期：
$ git rev-list --count --since=2016-03-02 --before=2016-03-03 HEAD
答案 2 :(得分：0)
我试过了：
git log | grep日期| awk＆＃39; {print＆＃34; ：＆＃34; $ 4＆＃34; ＆＃34; $ 3＃34; ＆＃34; $ 6}＆＃39; | uniq -c
它有效。你会得到类似的东西：
5 : 3 Mar 2016
4 : 2 Mar 2016
8 : 1 Mar 2016
[...]
我找到了命令here。