我很困惑，无法弄清楚如何使用存储在我的数据库中的值发送短信。
SMS将显示如下：('NAME'... Message content, etc..)，然后将使用用户在sqlite数据库上输入的联系号码发送消息。
这是我在注册时用来获取数据的代码。
public class LoginDataBaseAdapter {
static final String DATABASE_NAME = "login.db";
static final int DATABASE_VERSION = 1;
public static final int NAME_COLUMN = 1;
// TODO: Create public field for each column in your table.
// SQL Statement to create a new database.
static final String DATABASE_CREATE = "create table "+"LOGIN"+
"( " +"ID"+" integer primary key autoincrement,"+ "USERNAME text, PASSWORD text, NAME text, C1 integer, C2 integer); ";
// Variable to hold the database instance
public SQLiteDatabase db;
// Context of the application using the database.
private final Context context;
// Database open/upgrade helper
private DataBaseHelper dbHelper;
public LoginDataBaseAdapter(Context _context) {
context = _context;
dbHelper = new DataBaseHelper(context, DATABASE_NAME, null, DATABASE_VERSION);
}
public LoginDataBaseAdapter open() throws SQLException {
db = dbHelper.getWritableDatabase();
return this;
}
public void close()
{
db.close();
}
public SQLiteDatabase getDatabaseInstance()
{
return db;
}
public void insertEntry(String userName,String password, String name, String cn1, String cn2) {
ContentValues newValues = new ContentValues();
// Assign values for each row.
newValues.put("USERNAME", userName);
newValues.put("PASSWORD",password);
newValues.put("NAME",name);
newValues.put("C1", cn1);
newValues.put("C2", cn2);
// Insert the row into your table
db.insert("LOGIN", null, newValues);
// Toast.makeText(context, "Reminder Is Successfully Saved", Toast.LENGTH_LONG).show();
}
public int deleteEntry(String UserName) {
//String id=String.valueOf(ID);
String where="USERNAME=?";
int numberOFEntriesDeleted= db.delete("LOGIN", where, new String[]{UserName}) ;
// Toast.makeText(context, "Number fo Entry Deleted Successfully : "+numberOFEntriesDeleted, Toast.LENGTH_LONG).show();
return numberOFEntriesDeleted;
}
public String getSingleEntry(String userName) {
Cursor cursor = db.query("LOGIN", null, " USERNAME=?", new String[]{userName}, null, null, null);
if(cursor.getCount()<1) { // username doesn't exist
cursor.close();
return "NOT EXIST";
}
cursor.moveToFirst();
String password = cursor.getString(cursor.getColumnIndex("PASSWORD"));
cursor.close();
return password;
}
public boolean isExist (String userName) {
boolean exists;
Cursor cursor = db.query("LOGIN", null, " USERNAME=?", new String[]{userName}, null, null, null);
if (cursor.getCount()>0) { // username exists
exists = true;
cursor.close();
return exists;
}
return false;
}
public void updateEntry(String userName,String password) {
// Define the updated row content.
ContentValues updatedValues = new ContentValues();
// Assign values for each row.
updatedValues.put("USERNAME", userName);
updatedValues.put("PASSWORD", password);
String where="USERNAME = ?";
db.update("LOGIN",updatedValues, where, new String[]{userName});
}}
这是SignUpActivity
public class SignUpActivity extends AppCompatActivity {
Button bSignup;
TextView tvSign;
EditText etUN, etPW, etPW2, etFN, etC1, etC2;
LoginDataBaseAdapter loginDataBaseAdapter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_sign_up);
loginDataBaseAdapter = new LoginDataBaseAdapter(this);
loginDataBaseAdapter = loginDataBaseAdapter.open();
bSignup = (Button)findViewById(R.id.bSignup);
tvSign = (TextView)findViewById(R.id.tvSign);
etUN = (EditText)findViewById(R.id.etUN);
etPW = (EditText)findViewById(R.id.etPW);
etPW2 = (EditText)findViewById(R.id.etPW2);
etFN = (EditText)findViewById(R.id.etFN);
etC1 = (EditText)findViewById(R.id.etC1);
etC2 = (EditText)findViewById(R.id.etC2);
bSignup.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
String username = etUN.getText().toString();
String password = etPW.getText().toString();
String password2 = etPW2.getText().toString();
String name = etFN.getText().toString();
String c1 = etC1.getText().toString();
String c2 = etC2.getText().toString();
// check if fields are vacant
if (username.equals("") || password.equals("") || password2.equals("") || name.equals("")
|| c1.equals("")|| c2.equals("")) {
Toast.makeText(getApplicationContext(), "Incomplete Data", Toast.LENGTH_SHORT).show();
return;
}
// check if passwords 1 and 2 match
if (!password.equals(password2)) {
Toast.makeText(getApplicationContext(), "Passwords don't match. Please try again.", Toast.LENGTH_LONG).show();
return;
}
//check is username is still available for use
if (loginDataBaseAdapter.isExist(username)){
Toast.makeText(getApplicationContext(),"Username already taken. Please try again.", Toast.LENGTH_LONG).show();
return;
}
else {
// allow data to be saved in the database
loginDataBaseAdapter.insertEntry(username, password, name, c1, c2);
Toast.makeText(getApplicationContext(), "Account Successfully Created ", Toast.LENGTH_LONG).show();
Intent intent = new Intent(getApplicationContext(), MainActivity.class);
startActivity(intent);
}
}
});
tvSign.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Intent intent = new Intent(getApplicationContext(), MainActivity.class);
startActivity(intent);
}
});
}
}
我登录后，如何获取这些值（“即NAME，C1和C2”）并按下按钮发送短信？
更新
我在LoginDataBaseAdapter上使用过它。
public HashMap<String, String> getUserDetails(){
HashMap <String,String> user = new HashMap <String,String> ();
String selectQuery = "SELECT * FROM " + "LOGIN";
Cursor cursor = db.rawQuery(selectQuery, null);
// Move to first row
cursor.moveToFirst();
if(cursor.getCount()>0){
user.put("USERNAME", cursor.getString(1));
user.put("PASSWORD", cursor.getString(2));
user.put("NAME", cursor.getString(3));
user.put("C1", cursor.getString(4));
user.put("C2", cursor.getString(5));
}
cursor.close();
db.close();
// return user
return user;
}
然后我的HomeActivity上的代码：
tvHello = (TextView)findViewById(R.id.tvHello);
HashMap <String, String> details = loginDataBaseAdapter.getUserDetails();
String name_text = details.get("NAME");
tvHello.setText("Welcome " + name_text);
它似乎只能获得当前用户的第一个条目而不是当前条目。有什么想法来解决这个问题？非常感谢你。
答案 0 :(得分：0)
管理以使其正确。所以我会回答我自己的问题。
创建一个editText区域，您可以在其中输入要检索的名称。然后使用此代码检索它
public String getData(String verif) {
Cursor cursor = db.query("LOGIN", null, " USERNAME=?", new String[]{verif}, null, null, null);
if(cursor.getCount()<1) {
cursor.close();
return "No records exist";
}
cursor.moveToFirst();
String get_name = cursor.getString(cursor.getColumnIndex("NAME"));
cursor.close();
return get_name;
}
检索后，在TextView中设置名称。然后将其转换为字符串，如下所示：
String myName = myTextView.getText().toString();
然后：
smsManager.sendTextMessage(number, null, "My name is "+ myName ,null,
null);
＆＃39;数＆＃39;是一个字符串，其中包含您要发送短信的联系号码