Question

我的任务是加密和解密编码，还创建一个退出程序的按钮或单词。现在，我已经研究了如何做到这一点，但现在我必须使用ASCII，我需要一些帮助...这是我的代码，只需加密，解密和退出下面。任何人都可以帮我解决ASCII部分...

    welcome = input("Hello there...")
    letters = ("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z")

    numberShift = int(input("How much do you wish to shift the letters? "))
    phrase = input("Enter a phrase to be encrypted: ")
    newPhrase = ""
    for l in phrase:
    if l in letters:
    pos = letters.index(l) + numberShift
    if pos > 25:
        pos = pos - 26
    newPhrase += letters[pos]
else:
    newPhrase += " "
    print(newPhrase)

    numberShift = int(input("How many times has the code you want to decrypt been shifted? "))
    phrase = input("Enter a phrase to be decrypted: ")
    newPhrase = ""
    for l in phrase:
if l in letters:
    pos = letters.index(l) - numberShift
    if pos > 25:
        pos = pos - 26
    newPhrase += letters[pos]
else:
    newPhrase += " "
    print(newPhrase)

exit1 = input("Do you want to exit?")

if 'yes' in exit1:
   exit()

Answer 1

这是修复后的代码版本。在Python中，正确的缩进非常很重要，因为这是将代码分组为块的方式。如果代码缩进错误，那么Python解释器和阅读程序的人都无法告诉你想要它做什么。

我们可以将letters简化为单个字符串，而不是字符串元组。

我所做的主要更改是将letters以内的字符复制到newPhrase而不移动它们。这意味着空格和标点符号会被复制，但这也意味着数字和大写字母也会被复制。

我还将你的程序放到一个大循环中，这样"Do you want to exit? "的东西才有意义。否则，程序将会退出。

letters = "abcdefghijklmnopqrstuvwxyz" 

welcome = print("Hello there!")

while True:
    #Encrypt
    numberShift = int(input("How much do you wish to shift the letters? "))
    phrase = input("Enter a phrase to be encrypted: ")
    newPhrase = ""
    for l in phrase:
        #Only change characters that aren't in letters
        if l in letters:
            pos = letters.index(l) + numberShift
            if pos > 25:
                pos = pos - 26
            l = letters[pos]
        newPhrase += l

    print(newPhrase)

    #Decrypt
    numberShift = int(input("How many times has the code you want to decrypt been shifted? "))
    phrase = input("Enter a phrase to be decrypted: ")
    newPhrase = ""
    for l in phrase:
        #Only change characters that aren't in letters
        if l in letters:
            pos = letters.index(l) - numberShift
            if pos > 25:
                pos = pos - 26
            l = letters[pos]
        newPhrase += l

    print(newPhrase)

    if 'yes' in input("Do you want to exit? "):
        break

测试输出

Hello there!
How much do you wish to shift the letters? 3
Enter a phrase to be encrypted: somewhere in la mancha, in a place whose name I do not care to remember, a gentleman lived not long ago, one of those who has a lance and ancient shield on a shelf and keeps a skinny nag and a greyhound for racing.
vrphzkhuh lq od pdqfkd, lq d sodfh zkrvh qdph I gr qrw fduh wr uhphpehu, d jhqwohpdq olyhg qrw orqj djr, rqh ri wkrvh zkr kdv d odqfh dqg dqflhqw vklhog rq d vkhoi dqg nhhsv d vnlqqb qdj dqg d juhbkrxqg iru udflqj.
How many times has the code you want to decrypt been shifted? 3
Enter a phrase to be decrypted: vrphzkhuh lq od pdqfkd, lq d sodfh zkrvh qdph I gr qrw fduh wr uhphpehu, d jhqwohpdq olyhg qrw orqj djr, rqh ri wkrvh zkr kdv d odqfh dqg dqflhqw vklhog rq d vkhoi dqg nhhsv d vnlqqb qdj dqg d juhbkrxqg iru udflqj.
somewhere in la mancha, in a place whose name I do not care to remember, a gentleman lived not long ago, one of those who has a lance and ancient shield on a shelf and keeps a skinny nag and a greyhound for racing.
Do you want to exit? yes

任何人都可以帮我解决ASCII部分问题

1 个答案: