Question

我有以下记录集。

lgh_driver1 | lgh_number | Origin Company ID | First Pickup Company ID | Second Pickup Company ID | First Drop Company ID | Second Drop Company ID | Ending Company ID | Event Time
XXXXXX       111111        XXXXWAR                                                                                                                                       15
XXXXXX       111111                            GORMC                                                                                                                     199
XXXXXX       111111                                                      ERGCON                                                                                          944
XXXXXX       111111                                                                                  QUASAL                                                              45
XXXXXX       111111                                                                                                          QUASAL                                      45
XXXXXX       111111                                                                                                                                   XXXXWAR            15

理想情况下，我想要做的是将这些组合起来，以便我获得1 lgh驱动程序1 lgh数字，并且所有公司在一行中列出事件时间总和。我希望有一个相对简单的解决方案，我忽略了，但任何解决方案都会在这一点上做。任何想法或意见将不胜感激。谢谢。

Answer 1

如果每个lgh_number只有一个公司记录，则可以像这样使用SQL：

SELECT Table1.lgh_driver1, Table1.lgh_number, Max(Table1.[Origin Company ID]) AS [MaxOfOrigin Company ID], Max(Table1.[First Pickup Company ID]) AS [MaxOfFirst Pickup Company ID], Max(Table1.[Second Pickup Company ID]) AS [MaxOfSecond Pickup Company ID], Max(Table1.[First Drop Company ID]) AS [MaxOfFirst Drop Company ID], Max(Table1.[Second Drop Company ID]) AS [MaxOfSecond Drop Company ID]
FROM Table1
GROUP BY Table1.lgh_driver1, Table1.lgh_number;

最大聚合函数将为每个公司列返回非空值

将具有1个id的多个记录合并到Access中的1个记录中

1 个答案: