Question

Scanner s = new Scanner(System.in);
List<Integer> solutions = new LinkedList<>();
int o = 0;

while (o != 10) {        // I want to read 2 numbers from keyboard   
    int p = s.nextInt(); // until send and enter, this is where is my
    int c = s.nextInt(); //doubt
    int d = p + c;
    solutions.add(d);  
    o = System.in.read();
}

Iterator<Integer> solution = solutions.iterator();
while (solution.hasNext()) {
    int u = solution.next();
    System.out.println(u);
}

我遇到的问题是，我如何发送一个输入来结束循环？因为System.in.read（）取第一个数字，如果我放了另外2个数字，例子可能是，

输入：

2 3（输入）读取2个数字和总和

1 2（输入）读取2个数字和总和

（输入）并且这里因为输入而没有数字而结束循环并给出了解决方案

出口：

5

3

我不知道，如果我在

之前发布得很好

Answer 1

阅读整行并自行解析。如果该行为空，则退出循环结束该程序。如果它不是空的，则将该行传递给新的扫描仪。

List<Integer> solutions = new LinkedList<>();

Scanner systemScanner = new Scanner(System.in);
String line = null;

while ((line = systemScanner.nextLine()) != null && !line.isEmpty()) {
    Scanner lineScanner = new Scanner(line);
    int p = lineScanner.nextInt();
    int c = lineScanner.nextInt();
    int d = p + c;
    solutions.add(d);
}

Iterator<Integer> solution = solutions.iterator();
while (solution.hasNext()) {
    int u = solution.next();
    System.out.println(u);
}

停止键盘输入？

1 个答案: