Question

如果我们有以下数据，我想使用“SomeID”列或“ApplicationID”获取数据。因此，返回的数据基本上是基于“SomeID”

的单独列中的金额

  ID    SomeID ApplicationID    Amount
    19  8      19               45.18
    20  8      20               45.18
    21  8      21               225.91
    22  8      22               203.32
    72  10     19               45.18
    73  10     20               45.18
    74  10     21               225.91
    75  10     22               203.32

我想返回

Last Month repayment    This Month repaymnrt    Variance
45.18                   45.18                    0
45.18                   45.18                    0
225.91                  225.91                   0
203.32                  203.32                   0

Answer 1

我认为您可以使用pivot或条件聚合来执行您想要的操作：

select applicationId,
       sum(case when someId = 8 then Amount else 0 end) as LastMonth,
       sum(case when someId = 10 then Amount else 0 end) as ThisMonth,
       sum(case when someId = 8 then -Amount 
                when someId = 10 then Amount
                else 0
           end) as Diff
from t
group by applicationId;

如何在SQL中获取最新数据和以前的数据

1 个答案: