我想在我的c#源代码文件中获取一个方法。我已经用roslyn打开了解决方案并找到了如下方法符号
Roslyn.Compilers.Common.ISymbol s=GetMethodSymbolAtPosition (30);
我有一个ISymbol现在怎么样?
答案 0 :(得分:9)
Unfortunately, the IL generation is entirely hidden inside the Emit
call in Roslyn. But I'll give a simple to get you started.
Let's suppose you start of with an existing compilation:
var initial = CSharpCompilation.Create("Existing")
.AddReferences(MetadataReference.CreateFromFile(typeof(object).Assembly.Location))
.AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(@"
namespace Test
{
public class Program
{
public static void HelloWorld()
{
System.Console.WriteLine(""Hello World"");
}
}
}"));
var method = initial.GetSymbolsWithName(x => x == "HelloWorld").Single();
where method
is your ISymbol
. Then you can do following:
// 1. get source
var methodRef = method.DeclaringSyntaxReferences.Single();
var methodSource = methodRef.SyntaxTree.GetText().GetSubText(methodRef.Span).ToString();
// 2. compile in-memory as script
var compilation = CSharpCompilation.CreateScriptCompilation("Temp")
.AddReferences(initial.References)
.AddSyntaxTrees(SyntaxFactory.ParseSyntaxTree(methodSource, CSharpParseOptions.Default.WithKind(SourceCodeKind.Script)));
using (var dll = new MemoryStream())
using (var pdb = new MemoryStream())
{
compilation.Emit(dll, pdb);
// 3. load compiled assembly
var assembly = Assembly.Load(dll.ToArray(), pdb.ToArray());
var methodBase = assembly.GetType("Script").GetMethod(method.Name, new Type[0]);
// 4. get il or even execute
var il = methodBase.GetMethodBody();
methodBase.Invoke(null, null);
}
In a more complex case, you'd probably need to emit the entire/initial compilation, and get the generated method via reflection.
Refer to this post to find out what you can do with the results of GetMethodBody()
.