外接键盘连接时如何保存WebView状态？

Question

当我使用OTG（A4TECH GX-110）连接外部键盘时，我的Activity正在从头开始创建。这导致重新创建WebView。

这是我的XML：

    <?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context="uz.cp.oxmini.MainActivity">

    <WebView
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:id="@+id/wvOx" />

</RelativeLayout>

我尝试保存WebView状态，然后保存onCreate()方法以恢复已保存的状态。

private WebView mWebview;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    mWebview = new WebView(this);

    if (savedInstanceState != null){
        mWebview.restoreState(savedInstanceState);
    }
    else {
        mWebview.loadUrl("http://joerichard.net");
        setContentView(mWebview);
    }
}

@Override
protected void onSaveInstanceState(Bundle outState) {
    mWebview.saveState(outState);
}

但结果是带灰色背景的屏幕

有什么问题？怎么解决？

Answer 1

我添加了onRestoreInstanceState并修改了onSaveInstance方法。现在我在onRestoreInstanceState中恢复webview状态。此外，我已更改检查savedInstanceState是否为null：

        private WebView mWebview;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        mWebview = new WebView(this);

        if (savedInstanceState == null) {
            mWebview.loadUrl("http://joerichard.net");
        }

setContentView(mWebview);
    }


    @Override
    protected void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);
        mWebview.saveState(outState);
    }

    @Override
    protected void onRestoreInstanceState(Bundle savedInstanceState) {
        super.onRestoreInstanceState(savedInstanceState);
        mWebview.restoreState(savedInstanceState);
    }