查找对象是否是javascript中另一个对象的子集

时间：2016-03-02 02:27:01

标签： javascript lodash

我需要一个函数isSubset，当给定两个对象时，它会比较它的值并判断一个对象是否是另一个对象的子集。

object1 = { pickUpLocation : {city : 'Hyderabad', state: 'Telangana' }};
object2 = { dist : 322, pickUpLocation:  {city : 'Hyderabad', state: 'Telangana' }};

isSubset(object1, object2); //should return true

object3 = { pickUpLocation : {city : 'Chennai', state: 'Telangana' }}
object4 = { dist : 322, pickUpLocation: {city : 'Hyderabad', state: 'Telangana' }}

isSubset(object3, object4) //should return false as city's value is different

8 个答案:

答案 0 :(得分：9)

使用Lodash isMatch

_.isMatch({prop: 'object', id: 3}, {prop: 'object'})

  

在对象和源之间执行部分深度比较，以确定对象是否包含等效的属性值。

答案 1 :(得分：5)

您可以尝试使用isSubset包。

这是真的

isSubset(
  { dist : 322, pickUpLocation:  {city : 'Hyderabad', state: 'Telangana' }},
  { pickUpLocation : {city : 'Hyderabad', state: 'Telangana' }}
);

这是假的

isSubset(
  { dist : 322, pickUpLocation:  {city : 'Hyderabad', state: 'Telangana' }},
  { pickUpLocation : {city : 'Chennai', state: 'Telangana' }}
);

答案 2 :(得分：4)

使用lodash可以轻松完成。

import _ from 'lodash'

const isSubset = (aSubset, aSuperset) => (
    _.every(aSubset, (val, key) => _.isEqual(val, aSuperset[key]))
)

用法：

const object1 = { pickUpLocation: { city: 'Hyderabad', state: 'Telangana' }}
const object2 = { dist: 322, pickUpLocation:  { city: 'Hyderabad', state: 'Telangana' }}

isSubset(object1, object2)

答案 3 :(得分：0)

使用lodash的上述答案有限制，并未涵盖所有边缘情况。我刚刚提出了匹配所有场景的解决方案

def move_cursor_event(self, tree_view, step, count, extend_selection):
    rect = tree_view.get_cursor_locations()
    self.scroll_y(rect.strong.y)

def scroll_y(self, ypos):
    vadj = self.scrolled_window.get_vadjustment()
    vadj.set_value(ypos-80) 
    self.scrolled_window.set_vadjustment(vadj)

案例1：

import _ from 'lodash';

isSubset(obj1, obj2) {
  let matched = true;
  _.forEach(obj1, (value, key) => {
    if(!requirements || !_.isEqual(value, obj2[key])) {
      matched = false;
      return;
    }
  });
  return matched;
}

案例2：

const obj1 = { foo: 'bar' };
const obj2 = { foo: 'bar', baz: 'qux' };
console.log(isSubset(obj1, obj2)); // true

案例3：

const obj1 = { foo: 'bar' };
const obj2 = { foo: 'bar' };
console.log(isSubset(obj1, obj2)); // true

案例4：

const obj1 = { foo: 'bar', baz: 'qux' };
const obj2 = { foo: 'bar'};
console.log(isSubset(obj1, obj2)); // false

案例5：

const obj1 = undefiend;
const obj2 = undefiend;
console.log(isSubset(obj1, obj2)); // true

案例6：

const obj1 = undefiend;
const obj2 = { foo: 'bar'};
console.log(isSubset(obj1, obj2)); // true

答案 4 :(得分：0)

这是一个简单的解决方案：

  import _ from "lodash"
  // is a subset of b?
  function isSubset(a, b, merge = false) {
    const assign = merge ? _.merge : _.assign;
    var c = assign(_.cloneDeep(b), a);
    return _.isEqual(b, c);
  }

答案 5 :(得分：0)

也有点晚了，但这是另一种不需要任何外部库的解决方案。我基于@Akshay Kapoor 的回答，但是这个处理日期和定义 valueOf() 的其他对象的相等性：

const isSubset = (superObj, subObj) =>
    superObj === subObj ||
    typeof superObj === "object" &&
    typeof subObj === "object" && (
        subObj.valueOf() === superObj.valueOf() /* dates & ? */ ||
        Object.keys(subObj).every(k => isSubset(superObj[k], subObj[k]))
    );

答案 6 :(得分：-1)

function isSubset(obj1, obj2) {
  for (var key in obj2){
     if (JSON.stringify(obj2[key]) === JSON.stringify(obj1[key]))
        return true;
  }
  return false;
}

编辑：现在是通用的，但如果想要更通用，您应该看到比较的后续链接 https://stackoverflow.com/a/1144249/5965782

答案 7 :(得分：-1)

英文：

  

{ "status": "1", "result": [ { "RespAlunos": { "id": "5", "pessoas_id": "8", "pessoas_id1": "9", "created": "2015-09-21 10:25:46", "modified": "2015-09-21 10:25:46" }, "Responsavel": { "id": "8", "nome": "responsavel ", "email": "responsavel @hotmail.com", "tipopessoas_id": "3", "status": "1", "created": "2015-09-21 10:17:17", "modified": "2015-09-21 10:17:17" }, "Aluno": { "id": "9", "nome": "aluno", "email": "aluno@gmail.com", "tipopessoas_id": "1", "status": "1", "created": "2015-09-21 10:18:41", "modified": "2015-09-21 10:18:41" }, "Matricula": { "id": "6", "referencia": "238", "pessoas_id": "9", "turmas_id": "4", "escolas_id": "2", "status": "1", "created": "2015-09-21 10:35:08", "modified": "2016-02-18 10:51:20" }, "Turma": { "id": "4", "descricao": "4º ano", "created": "2015-09-21 10:31:32", "modified": "2015-09-21 10:31:32" }, "Escola": { "id": "2", "descricao": "Santa Luz Unidade 2", "created": "2015-09-17 23:09:38", "modified": "2015-09-17 23:09:38" }, "Agenda": { "id": "34", "data": "2016-02-29 14:40:00", "descricao": "<p>teste 1</p>\r\n", "escolas_id": "2", "turmas_id": "4", "created": "2016-02-29 14:40:21", "modified": "2016-02-29 14:40:21" } }, { "RespAlunos": { "id": "5", "pessoas_id": "8", "pessoas_id1": "9", "created": "2015-09-21 10:25:46", "modified": "2015-09-21 10:25:46" }, "Responsavel": { "id": "8", "nome": "responsavel ", "email": "responsavel @hotmail.com", "tipopessoas_id": "3", "status": "1", "created": "2015-09-21 10:17:17", "modified": "2015-09-21 10:17:17" }, "Aluno": { "id": "9", "nome": "aluno", "email": "aluno@gmail.com", "tipopessoas_id": "1", "status": "1", "created": "2015-09-21 10:18:41", "modified": "2015-09-21 10:18:41" }, "Matricula": { "id": "6", "referencia": "238", "pessoas_id": "9", "turmas_id": "4", "escolas_id": "2", "status": "1", "created": "2015-09-21 10:35:08", "modified": "2016-02-18 10:51:20" }, "Turma": { "id": "4", "descricao": "4º ano", "created": "2015-09-21 10:31:32", "modified": "2015-09-21 10:31:32" }, "Escola": { "id": "2", "descricao": "Santa Luz Unidade 2", "created": "2015-09-17 23:09:38", "modified": "2015-09-17 23:09:38" }, "Agenda": { "id": "27", "data": "2016-02-29 08:24:00", "descricao": "descricao", "escolas_id": "2", "turmas_id": "4", "created": "2016-02-29 08:25:20", "modified": "2016-02-29 08:25:20" } } ] } 中是否有某些键，以确保其值与object2之间存在深相等的条件？

写出来：

object1

以较短的形式：

_.some(                       // Is there some key
  object2,                    // in object2
  function(val, key) {             // which satisfies the condition that
    return _.isEqual(         // there is deep equality between
      val,                    // its value and
      object1[key]                 // object1?
    );
  }
);

在ES6中：

_.some(object2, function(val, key) { return _.isEqual(val, object1[key]); })

我的建议是阅读lodash docs并了解所有API，或至少是主要API。例如，如果您不了解_.some(object2, (val, key) => _.isEqual(val, object1[key])) 和_.some等重要例程，则很难自行解决此问题。另一方面，如果你确实了解它们，那就非常简单了。

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