Question

我尝试使用一些web api，所以我这样做

public static void main(String[] args) {
    // Create Jersey client
    Client client = Client.create();

    // GET request to findBook resource with a query parameter
    String getSoccersSeasonsUrl = "http://api.football-data.org/v1/soccerseasons";
    WebResource webResourceGet = client.resource(getSoccersSeasonsUrl);
    webResourceGet.header("X-Auth-Token", myToken);
    ClientResponse response = webResourceGet.get(ClientResponse.class);
    String output = response.getEntity(String.class);

    System.out.println(output);
}

输出

[{"_links":{"self":{"href":"http://api.football-data.org/v1/soccerseasons/394"},"teams":{"href":"http://api.football-data.org/v1/soccerseasons/394/teams"},"fixtures":{"href":"http://api.football-data.org/v1/soccerseasons/394/fixtures"},
"leagueTable":{"href":"http://api.football-data.org/v1/soccerseasons/394/leagueTable"}},
"id":394,
"caption":"1. Bundesliga 2015/16",
"league":"BL1",
"year":"2015",
"currentMatchday":24,
"numberOfMatchdays":34,
"numberOfTeams":18,
"numberOfGames":306,
"lastUpdated":"2016-03-01T20:50:44Z »}

如何从这个输出中直接填充对象的java ArrayList，如：

public class SoccerSeason {
    public SoccerSeason() {
    }
    private long id;
    private String caption;
    private String league;
    private String year;
    private long currentMatchday;
    private long numberOfMatchdays;
    private long numberOfTeams;
    private long numberOfGames;
    private String lastUpdated;
}

当我试图直接获得SoccerSeason output = response.getEntity（SoccerSeason.class）;我有一个经典的com.sun.jersey.api.client.ClientHandlerException 请问我的代码中缺少什么？你知道如何做到这一点吗？

Answer 1

你想要的是谷歌的GSON。它可以通过快速谷歌搜索找到，它有大量易于阅读的文档。

将GSON添加到项目依赖项/源代码中，将所有类成员的getter和setter添加到您创建的类中，它应该可以很好地工作。

它的用法如下：

subprocess.check_output([command]) //returns immediately
subprocess.check_output([command, "-i"]) // takes longer to run, returns output
subprocess.call([command]) // also takes longer to run

其中Gson gson = new Gson(); SoccerSeason newSoccerSeason = gson.fromJson(webApiResponse, SoccerSeason.class); String lastUpdated = newSoccerSeason.getLastUpdated();是作为Web API响应收到的JSON的String表示形式。您还可以定义类webApiResponse，如下所示：

SoccerSeasonList

当然，您传入的JSON必须有一个名为seasonList的对象，其中包含您的所有public class SoccerSeasonList { ArrayList<SoccerSeason> seasonList; // getters/setters }个对象以匹配此定义。

但是，你可以像这样抓住你的名单：

SoccerSeason

执行如下操作：

SoccerSeasonList seasonList = gson.fromJson(webApiResponse, SoccerSeasonList.class);
ArrayList<SoccerSeason> seasonArr = seasonList.getSeasonList();

回顾一下：您只需将JSON对象名称和文字与类中的等效java类型相匹配，并在包含从您要解析的Web API接收的JSON的String上调用fromJSON，并传入你想要解析对象的类。

将WebResource中的JSON解析为可用的Java对象

1 个答案: