如何忽略以function add($arr){
extract($arr, EXTR_REFS);
return $one+$two;
}
$one = 1;
$two = 2;
echo add(compact('one', 'two')); // 3
开头并以...结尾的注释语句
例如"/*"
:"*/"
或
/*the problem is..*/
,我想逐行读取java文件时删除这些语句
/* problem is very difficult */
答案 0 :(得分:-1)
只需包括:
int index = str.indexOf("/*");
while(index != -1) {
str = str.substring(0, index) + str.substring(str.indexOf("*/")+2);
index = str.indexOf("/*");
}
修改强>
假设您必须考虑片段的开头或结尾中断注释的片段:
的 EDIT2:强>
现在..还假设您必须考虑文字字符串"/*"
或"*/"
str = str.replace("\"/*\"", "literal_string_open_comment");
str = str.replace("\"*/\"", "literal_string_close_comment");
int start = str.indexOf("/*"), end = str.indexOf("*/");
while(start > -1 || end > -1) {
if(start != -1) {
if(end != -1) {
if(end < start) {
str = str.substring(end+2);
} else {
str = str.substring(0, start) + str.substring(end+2);
}
} else {
str = str.substring(0, start);
}
} else {
str = str.substring(end+2);
}
start = str.indexOf("/*");
end = str.indexOf("*/");
}
str = str.replace("literal_string_open_comment", "\"/*\"");
str = str.replace("literal_string_close_comment", "\"*/\"");