Question

我设法制作一个完全正常的记分牌，但它有一个小问题。我总是将我的“地点”数字增加1.如果两个竞争者的结果相同，他们应该有相同的“地点”。

目前我的代码（只有PHP我在表中回应它）：

<?php

          while( $row = mysql_fetch_assoc( $u10z ) ){

            print "<tr>";

            print "<td>" . $i1 . "</td>";           

            print "<td>" . $row['ime'] . "</td>"; 

            print "<td>" . $row['priimek'] . "</td>"; 

            print "<td>" . $row['klub'] . "</td>";

            print "<td>" . $row['drzava'] . "</td>";

            print "<td>" . $row['vrh'] . "</td>";

            print "<td>" . $row['vrhPoskus'] . "</td>";

            print "<td>" . $row['bonus'] . "</td>";

            print "<td>" . $row['bonusPoskus'] . "</td>";

            print "</tr>";

            $i1++;

          }

        ?>

正如您所见，$i1是一个“地点”计数器。

实施例： example image of results

如果你看第二张桌子，first(1)和second(2)竞争对手都应该在first(1)位置，因为它们都有相同的分数。

eighth(8)和ninth(9)竞争者也应该在eighth(8)位置。

修改

我现在正在使用下面评论的代码，但我有一点问题。数字被转移了。

<?php

    $pre_vrh = false;
    $pre_vrhPoskus = false;
    $pre_bonus = false;
    $pre_bonusPoskus = false;
    while( $row = mysql_fetch_assoc( $u10z ) ){
        print "<tr>";
        print "<td>" . $i1 . "</td>";           
        print "<td>" . $row['ime'] . "</td>"; 
        print "<td>" . $row['priimek'] . "</td>"; 
        print "<td>" . $row['klub'] . "</td>";
        print "<td>" . $row['drzava'] . "</td>";
        print "<td>" . $row['vrh'] . "</td>";
        print "<td>" . $row['vrhPoskus'] . "</td>";
        print "<td>" . $row['bonus'] . "</td>";
        print "<td>" . $row['bonusPoskus'] . "</td>";
        print "</tr>";

        if ($pre_vrh != $row['vrh'] || $pre_vrhPoskus != $row['vrhPoskus'] || $pre_bonus != $row['bonus'] || $pre_bonusPoskus != $row['bonusPoskus']) {
            $i1++;
        }
        $pre_vrh = $row['vrh'];
        $pre_vrhPoskus = $row['vrhPoskus'];
        $pre_bonus = $row['bonus'];
        $pre_bonusPoskus = $row['bonusPoskus'];
      }

   ?>

图像： New results

Answer 1

在谈论得分时，我无法理解你的意思，但......看起来如果$row['vrh'], $row['vrhPoskus'], $row['bonus'], $row['bonusPoskus']是相同的，那么地方必须是相同的。如果代码可以像这样，那就是真的

<?php

    $pre_vrh = false;
    $pre_vrhPoskus = false;
    $pre_bonus = false;
    $pre_bonusPoskus = false;
    $place = 1;
    $i1 = 0;
    while( $row = mysql_fetch_assoc( $u10z ) ){
        print "<tr>";

        // we should compare old and new values for getting place
        if ($pre_vrh != $row['vrh'] || $pre_vrhPoskus != $row['vrhPoskus'] || $pre_bonus != $row['bonus'] || $pre_bonusPoskus != $row['bonusPoskus']) {
            $place = $i1 + 1;
        }
        $i1++;

        print "<td>" . $place . "</td>";           
        print "<td>" . $row['ime'] . "</td>"; 
        print "<td>" . $row['priimek'] . "</td>"; 
        print "<td>" . $row['klub'] . "</td>";
        print "<td>" . $row['drzava'] . "</td>";
        print "<td>" . $row['vrh'] . "</td>";
        print "<td>" . $row['vrhPoskus'] . "</td>";
        print "<td>" . $row['bonus'] . "</td>";
        print "<td>" . $row['bonusPoskus'] . "</td>";
        print "</tr>";


        $pre_vrh = $row['vrh'];
        $pre_vrhPoskus = $row['vrhPoskus'];
        $pre_bonus = $row['bonus'];
        $pre_bonusPoskus = $row['bonusPoskus'];
    }    
?>

Php + MySQL记分牌

1 个答案: