在Teradata中一次获得多个百分位数(percentile_cont等价物)

时间:2016-03-01 21:04:15

标签: sql teradata analytic-functions

我知道我们可以在Teradata中重写percentile_cont

SELECT
  part_col
  ,data_col
   + ((MIN(data_col) OVER (PARTITION BY part_col ORDER BY data_col ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) - data_col)
       * (((COUNT(*) OVER (PARTITION BY part_col) - 1) * x) MOD 1)) AS percentile_cont
FROM tab
QUALIFY ROW_NUMBER() OVER (PARTITION BY part_col ORDER BY data_col)
    = CAST((COUNT(*) OVER (PARTITION BY part_col) - 1) * x AS INT) + 1;

有关详细信息,请参阅this very helpful discussion

了解用x替换0.90会返回第90个百分点,是否有一种优雅的方式来扩展它并在一次传递中返回多个百分位数?

例如,假设我想扩展此示例并在一次传递中返回第25,50和75百分位数?这可能吗?好像我需要多个QUALIFY语句?同样,如果我需要多个GROUP BY个等价物,这类似于在PARTITION BY中传递更多列吗?

-- SQL:2008 Equivalent pseudo-code
SELECT
  part_col_a
 ,part_col_b
 ,PERCENTILE_CONT(0.25) WITHIN GROUP (ORDER BY order_col) AS p25
 ,PERCENTILE_CONT(0.50) WITHIN GROUP (ORDER BY order_col) AS p50
 ,PERCENTILE_CONT(0.75) WITHIN GROUP (ORDER BY order_col) AS p75
FROM tab
GROUP BY
  part_col_a
  ,part_col_b

1 个答案:

答案 0 :(得分:3)

你应该完全阅读我的博客,最终的查询正是你想要的: - )

SELECT part_col
  ,MIN(pc25) OVER (PARTITION BY part_col) AS quartile_1
  ,MIN(pc50) OVER (PARTITION BY part_col) AS quartile_2
  ,MIN(pc75) OVER (PARTITION BY part_col) AS quartile_3
FROM
 (
  SELECT
    part_col
    ,COUNT(*)      OVER (PARTITION BY part_col) - 1 AS N
    ,ROW_NUMBER()  OVER (PARTITION BY part_col ORDER BY data_col) - 1 AS rowno
    ,MIN(data_col) OVER (PARTITION BY part_col ORDER BY data_col ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) - data_col AS diff

    ,CASE
       WHEN rowno = CAST(N * 0.25 AS INT)
       THEN data_col +(((N * 0.25) MOD 1) * diff)
     END AS pc25

    ,CASE
       WHEN rowno = CAST(N * 0.50 AS INT)
       THEN data_col +(((N * 0.50) MOD 1) * diff)
     END AS pc50

    ,CASE
       WHEN rowno = CAST(N * 0.75 AS INT)
       THEN data_col +(((N * 0.75) MOD 1) * diff)
     END AS pc75
  FROM tab
  QUALIFY   rowno = CAST(N * 0.25 AS INT)
       OR   rowno = CAST(N * 0.50 AS INT)
       OR   rowno = CAST(N * 0.75 AS INT)
 ) AS dt
QUALIFY ROW_NUMBER() OVER (PARTITION BY part_col ORDER BY part_col) = 1