Question

我有一个字符串数字数组，例如：

numbers = ['10', '8', '918', '101010']

当我使用sorted(numbers)时，我会按字典顺序对它们进行排序，例如'8' > '17'。

如何迭代根据数值排序的字符串？

Answer 1

您可以使用带有键console.log('Script loaded...'); $(".btn-reg").on("click", reg); function reg(event) { console.log('Klick, klick...'); event.preventDefault(); // prevents the form to be submitted var newusername = $(".newusername").val(); var newpassword = $(".newpassword").val(); var newclub = $(".newclub").val(); $.post('classCalling.php', { newusername: newusername, newpassword: newpassword, newclub: newclub }, function(data) { console.log(data); } }); }的内置sorted()函数将列表中的每个项目映射到整数之前的整数：

int

<强>输出

numbers = ['10', '8', '918', '101010']
numbers = sorted(numbers, key=int)
print(numbers)

使用此方法将根据需要输出字符串列表。

Answer 2

您可以使用内置的map函数将数组元素转换为整数。

    MapObject mapPlayer = currentMap.getLayers().get("objects").getObjects().get("player");
MapObjects mapObject = currentMap.getLayers().get("objects").getObjects();
for (Iterator<String> iter = mapPlayer.getProperties().getKeys(); iter.hasNext(); )
{
    System.out.println("#############"+iter.next());
}
System.out.println("**************** player name :  " + mapPlayer.getProperties().get("name", String.class));
RectangleMapObject rect = (RectangleMapObject) mapObject.get("player");
float x = (float) rect.getRectangle().x;
float y = (float) rect.getRectangle().y;
float width = rect.getRectangle().width;
float height = rect.getRectangle().height;

System.out.println("**************** player coordinates X :  " +x);
System.out.println("**************** player coordinates Y:  "+y);
System.out.println("**************** player coordinates width :  " +width);
System.out.println("**************** player coordinates height:  "+height);
System.out.println("**************** player coordinates X :  " +mapPlayer.getProperties().get("x", Integer.class));
System.out.println("**************** player coordinates Y:  "+mapPlayer.getProperties().get("y", Integer.class));
System.out.println("**************** player velocity :  "+mapPlayer.getProperties().get("velocity", Integer.class));

输出：

print sorted(map(int, numbers))

Answer 3

如果您想保留为字符串，可以将int作为list.sort的密钥传递给numbers = ['10', '8', '918', '101010'] numbers.sort(key=int)，这将对原始列表进行排序：

/dir1/dir2/dir3/filename

Answer 4

我喜欢这样做，这非常快。

composer install

Answer 5

所有元素类型都是字符串，

 >>> x=['4', '5', '29', '54', '4', '0', '-214', '542', '-64', '1', '-3', '6', '-6']
 >>> max(x)
 '6'

它按字母顺序对单词进行“排序”，并返回字母列表底部的单词

更多示例：

    >>> list1 = ['kyle', 'dhamu']
    >>> max(list1)
    'kyle'

返回kyle，因为k在d之后

还请记住，从python3.7开始，您不能将字符串和整数混合使用max函数。下面是示例

>>> mix_list = ['my', 'name', 'is', 1 ]
>>> max(mix_list)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: '>' not supported between instances of 'int' and 'str'

Python：不按字典顺序排序字符串数字

5 个答案: