Question

我正在尝试使用rapidjson创建一个json，并且在生成正确的输出时遇到了一些意想不到的问题。

我正在创建和填充这样的文档：

Document d;
d.SetObject();

rapidjson::Document::AllocatorType& allocator = d.GetAllocator();

size_t sz = allocator.Size();

d.AddMember("version",  1, allocator);
d.AddMember("testId",   2, allocator);
d.AddMember("group",    3, allocator);
d.AddMember("order",    4, allocator);

Value tests(kArrayType);
Value obj(kObjectType);
Value val(kObjectType);

obj.AddMember("id", 1, allocator);

string description = "a description";
val.SetString(description.c_str(), static_cast<SizeType>(description.length()), allocator);
obj.AddMember("description", val, allocator);

string help = "some help";
val.SetString(help.c_str(), static_cast<SizeType>(help.length()), allocator);
obj.AddMember("help", val, allocator);

string workgroup = "a workgroup";
val.SetString(workgroup.c_str(), static_cast<SizeType>(workgroup.length()), allocator);
obj.AddMember("workgroup", val, allocator);

val.SetBool(true);
obj.AddMember("online", val, allocator);

tests.PushBack(obj, allocator);
d.AddMember("tests", tests, allocator);

// Convert JSON document to string
rapidjson::StringBuffer strbuf;
rapidjson::PrettyWriter<rapidjson::StringBuffer> writer(strbuf);
d.Accept(writer);

当我运行此代码时，我希望获得此json：

{
    "version": 1,
    "testId": 2,
    "group": 3,
    "order": 4,
    "tests": [
        {
            "id": 1,
            "description": "a description",
            "help": "some help",
            "workgroup": "a workgroup",
            "online": true
        }
    ]
}

但实际生成的输出是......

{
    "version": 1,
    "testId": 2,
    "group": 3,
    "order": 4,
    "tests": [
        {
            "id": 1,
            "description": "a description",
            "help": "some help",
            "workgroup": "a workgroup",
            "online": tr{
    "version": 1,
    "testId": 2,
    "group": 3,
    "order": 4,
    "tests": [
        {
            "id": 1,
            "description": "a description",
            "help": "some help",
            "workgroup": "a workgroup",
            "online": true
        }
    ]
}

有什么想法吗？

Answer 1

最后，我设法跟踪问题，直到我在VS中使用OutputDebugString输出字符串的方式。如果我保存了结果字符串（由GetString()给出），则输出符合预期！

我的调试陷阱挫败了！

rapidjson正确的json创作

1 个答案: