Question

我正在使用Android的SQLite

我的架构：

templateUrl: 'client/templates/tabset.html'

我正在尝试使用的触发器：

CREATE TABLE timecards (
 id INTEGER PRIMARY KEY,
 template_id INTEGER,
 autofill_id INTEGER,
 employee_name TEXT,
 production_name TEXT,
 week_ending TEXT,
 FOREIGN KEY(template_id) REFERENCES templates(id),
 FOREIGN KEY(autofill_id) REFERENCES autofills(id)
);

CREATE TABLE timecard_fields (
 id INTEGER PRIMARY KEY,
 timecard_id INTEGER,
 timecard_field_name TEXT,
 timecard_field_value TEXT,
 FOREIGN KEY(timecard_id) REFERENCES timecards(id)
);

CREATE TABLE autofills (
 id INTEGER PRIMARY KEY,
 template_id INTEGER,
 last_used TEXT DEFAULT CURRENT_TIMESTAMP
);

CREATE TABLE autofill_fields (
 id INTEGER PRIMARY KEY,
 autofill_id INTEGER,
 autofill_field_name TEXT,
 autofill_field_value TEXT,
 FOREIGN KEY(autofill_id) REFERENCES autofills(id)
);

CREATE TABLE templates (
 id INTEGER PRIMARY KEY,
 template_name TEXT
);

我知道这是一个复杂的触发器。想法是从另一个表中提取值。我不确定它是否正确，但是，当我替换此触发器时，我得到相同的语法错误：

CREATE TRIGGER timecard_employee_name_delete_trigger DELETE ON timecard_fields
WHEN OLD.timecard_field_name='employee_name'
BEGIN
    UPDATE timecards
         SET employee_name = (SELECT af.autofill_field_value FROM autofills af WHERE af.autofill_id = autofill_id AND af.autofill_field_name = 'employee_name')
         WHERE id=OLD.timecard_id;
END;

此错误始终出现在触发器内的第一个查询中：

（1）near“;”：语法错误

INSERT INTO查询在触发器之外工作正常。

任何想法都会受到赞赏。

Answer 1

结果发现VIEW是处理此问题的更好方法。这就是我想出的：

CREATE VIEW timecard_info_view AS
SELECT DISTINCT timecards.id AS timecard_id,
templates.template_name AS template_name,
timecards.autofill_id AS autofill_id,
(SELECT CASE
  WHEN ((SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='employee_name' AND timecard_fields.timecard_id=timecards.id) IS NOT NULL)
THEN
  (SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='employee_name' AND timecard_fields.timecard_id=timecards.id)
ELSE
  (SELECT autofill_fields.autofill_field_value FROM autofill_fields
  WHERE autofill_fields.autofill_field_name='employee_name' AND autofill_fields.autofill_id=timecards.autofill_id)
END) AS employee_name,
(SELECT CASE
  WHEN ((SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='picture' AND timecard_fields.timecard_id=timecards.id) IS NOT NULL)
THEN
  (SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='picture' AND timecard_fields.timecard_id=timecards.id)
ELSE
  (SELECT autofill_fields.autofill_field_value FROM autofill_fields
  WHERE autofill_fields.autofill_field_name='picture' AND autofill_fields.autofill_id=timecards.autofill_id)
END) AS production_name,
(SELECT CASE
  WHEN ((SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='week_ending' AND timecard_fields.timecard_id=timecards.id) IS NOT NULL)
THEN
  (SELECT timecard_fields.timecard_field_value FROM timecard_fields
  WHERE timecard_fields.timecard_field_name='week_ending' AND timecard_fields.timecard_id=timecards.id)
ELSE
  (SELECT autofill_fields.autofill_field_value FROM autofill_fields
  WHERE autofill_fields.autofill_field_name='week_ending' AND autofill_fields.autofill_id=timecards.autofill_id)
END) AS week_ending
FROM timecards
LEFT JOIN templates
ON timecards.template_id=templates.id
LEFT JOIN timecard_fields
ON timecard_fields.timecard_id=timecards.id
LEFT JOIN autofill_fields
ON timecards.autofill_id=autofill_fields.id

任何查询结束时的SQLite触发器语法错误

1 个答案: