所以我试图在这里使用它：
http://codepen.io/dudleystorey/pen/Geprd
现在它部分有效。
目前，如果您使用该演示，您可以看到 CREATE TRIGGER [dbo].[ax_Triger] ON [dbo].[extraTable]
FOR INSERT, UPDATE, DELETE AS
SET NOCOUNT ON;
--Capture the Operation (Inserted, Deleted Or Updated)
DECLARE @operation int
DECLARE @Count AS INT
SET @operation = 1
SELECT @Count = COUNT(*)
FROM DELETED
IF @Count > 0
BEGIN
SET @operation = 3
SELECT @Count = COUNT(*)
FROM INSERTED
IF @Count > 0
SET @operation = 2
END
DECLARE tmpUpit CURSOR FOR
SELECT i.id FROM inserted i
OPEN tmpUpit
FETCH NEXT FROM tmpUpit
into @ID WHILE @@fetch_status = 0
begin If Not exists
(SELECT * FROM mytable
where (Operation=3 OR (Operation=1 AND ID=@ID)) AND Status = 0 AND Tablename ='extraTable')
begin INSERT INTO
mytable ([Field1], [Field2],
[ID], [Tablename], [Operation], [Time12], [Status])
VALUES (@Field1, @Field2, @ID, 'extraTable', @operation,GETDATE(),0)
DELETE FROM mytable
WHERE [Field1]=@Field1 And [Field2]=@Field2 And [ID]=@ID And [Tablename]='extraTable'
AND [Operation] = 4 AND [Status] = 0
End
FETCH NEXT FROM tmpUpit into @ID
End CLOSE tmpUpit DEALLOCATE tmpUpit end
被推到左侧。
对我来说这是一个小问题，因为我有多个可能因此而改变的事情。
目前，我的表由jQuery填充。表格行需要大约2-3秒才能加载。
问题是，如果响应中没有任何内容我将th's跨越6列。当我真的需要忽略它时，JavaScript会尝试在里面添加列标题。
当表格中确实存在信息时，它似乎也无法显示表格标题。
我的控制台出现了错误：
Nothing found这就是这一行：
Uncaught TypeError: Cannot read property 'rows' of null
现在我必须将表单ID更改为类，因为我已经在其他地方使用了ID。如果这会产生巨大的差异。
谢谢，
萨姆