如果我有2个相同的节点，如何将文件xml转换为文本？

Question

我有一个像这样的XML文件，

<SellingCode>

<LastUpdated>2016-01-05T08:36:53+00:00</LastUpdated>

<SellingCodeID>5045460018689</SellingCodeID>

<SellingCodeID>103018090008</SellingCodeID>

<ProductID>1030180900</ProductID>

</SellingCode>

如何生成这样的数据

2016-01-05T08:36:53+00:00 | 5045460018689 | 1030180900

2016-01-05T08:36:53+00:00 | 103018090008  | 1030180900

你们有没有想过我在c＃中怎么做？

Answer 1

反序列化到下面的类，然后迭代/ lync以获得您所追求的格式。

[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public class SellingCode
{

    private System.DateTime lastUpdatedField;

    private ulong[] sellingCodeIDField;

    private uint productIDField;

    /// <remarks/>
    public System.DateTime LastUpdated
    {
        get
        {
            return this.lastUpdatedField;
        }
        set
        {
            this.lastUpdatedField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("SellingCodeID")]
    public ulong[] SellingCodeID
    {
        get
        {
            return this.sellingCodeIDField;
        }
        set
        {
            this.sellingCodeIDField = value;
        }
    }

    /// <remarks/>
    public uint ProductID
    {
        get
        {
            return this.productIDField;
        }
        set
        {
            this.productIDField = value;
        }
    }
}

Answer 2

LINQ to XML将为您效劳。

var document = XDocument.Load("file.xml");
var array = document.Descendants("COL").Select(x => (int) x).ToArray();