Question

大家好，

我在AngularJS中创建了一个包含多列的select示例。如果我像这样直接传递值，这工作正常：

$scope.rowDatas = [
                     { ID: "09-14-002880", PatientName: "PRAVEEN KUMAR", Gender: "Male", Age: "20", mobileNumber: 9879878971, patientId: "test" },
                     { ID: "09-13-000188", PatientName: "VAR", Gender: "Male", Age: "20", mobileNumber: '', patientId: "ZXC12" },
                     { ID: "09-05-019825", PatientName: "KARMA", Gender: "Male", Age: "29", mobileNumber: '', patientId: "ZA2545635" },
                     { ID: "09-04-010524", PatientName: "FRANKLIN ANTHONY", Gender: "Male", Age: "20", mobileNumber: '', patientId: "Z7552396" },
                     { ID: "09-08-009303", PatientName: "DARYOUSH", Gender: "Male", Age: "29", mobileNumber: '', patientId: "Z2548467" },
                     { ID: "09-12-031048", PatientName: "SMITA", Gender: "Female", Age: "20", mobileNumber: 9880222187, patientId: "Z2296538" },
                     { ID: "09-11-026001", PatientName: "ADITYA DILIP", Gender: "Male", Age: "29", mobileNumber: '', patientId: "Z2277913" }
    ];

但我真正需要的是我需要从工厂获得价值

dtfactory.getdata().then(function(response){
  //$scope.rowDatas = response.data;
})

这里response.data也包含相同的数据。如果我评论直接代码并取消注释工厂代码它不工作，我可能知道我错在哪里？任何人都可以帮助我。

Answer 1

尝试在控制器中执行此操作

$scope.rowDatas = dtfactory.getdata().then(function(response){
  $scope.rowDatas = response.data;
})

Answer 2

请尝试以下代码：

首先获取json数据并调用displayTable函数：

   dtfactory.getdata().then(function(response){
      $scope.rowDatas = response.data;
      dispalyTable();
    })

    function dispalyTable(){
      $scope.gridOptions = {
                    columnDefs: $scope.gridheaders,
                    rowData: $scope.rowDatas,
                };

         //document.addEventListener('DOMContentLoaded', function() {
            var gridDiv = document.querySelector('#myGrid_'+textBoxId);
            new agGrid.Grid(gridDiv, $scope.gridOptions);
         //}); 
    }

在AngularJS中选择多列不能正常工作？

2 个答案: