Question

这是我用来保存序列化数据的模型..当我运行主要属性（name，surname ..）时，从xml设置好，但是嵌套对象（检查）的属性（id，date，comment）为null在里面

代码中的哪些内容会解决这个问题？

namespace WpfApplication1
{
    [Serializable, XmlRoot("patients")]
    public class patients
    {
        [XmlElement("patient")]
        public List<patient> patients_list { get; set; }

    }
    public class patient
    {
        [XmlElement("firstname")]
        public string name { get; set; }
        [XmlElement("lastname")]
        public string surname { get; set; }
        [XmlElement("age")]
        public int age { get; set; }
        public string gender { get; set; }
        [XmlElement("exams")]
        public List<exam> exam { get; set; }

    }
    [XmlRoot("exams")]
    public class exam
    {
        [XmlElement("id")]
        public int id { get; set; }
        public DateTime date { get; set; }
        [XmlElement("comment")]
        public string comment { get; set; }
    }
}

和我的主要代码进行序列化：

System.Xml.Serialization.XmlSerializer reader =
                        new System.Xml.Serialization.XmlSerializer(typeof(patients));
                System.IO.StreamReader file = new System.IO.StreamReader("data.xml");
                var asd = (patients)reader.Deserialize(file);

和xml文件：

<patients>
 <patient>
    <firstname>Patience_name_1</firstname>
    <lastname>Patience_surname_1</lastname>
    <age>20</age>
    <gender>Male</gender>
    <exams>
      <exam>
        <id>1</id>
        <date>2/29/2016 12:18:44</date>
        <comment value="patiente">Exam completed for patience1</comment>
      </exam>
    </exams>
  </patient>
  <patient>
    <firstname>Patience_name_2</firstname>
    <lastname>Patience_surname_2</lastname>
    <age>22</age>
    <gender>Male</gender>
    <exams>
      <exam>
        <id>2</id>
        <date>2/29/2016 12:18:44</date>
        <comment value= "sdsad">Exam completed fro patience 2</comment>
      </exam>
    </exams>
  </patient>
  <patient>
    <firstname>Patience_name_3</firstname>
    <lastname>Patience_surname_3</lastname>
    <age>23</age>
    <gender>Female</gender>
    <exams>
      <exam>
        <id>3</id>
        <date>2/29/2016 12:18:44</date>
        <comment>Exam completed for patience 3</comment>
      </exam>
    </exams>
  </patient>
</patients>

Answer 1

您有以下问题：

您的exams列表的外容器元素<exams>包含每个项目的内部元素<exam>：
```
<exams>
  <exam>
    
  </exam>
  <exam>
    
  </exam>
<exams>
```
要使用外部容器元素序列化列表，请使用XmlArray和XmlArrayItem。
您的日期字符串不在ISO 8601 format之内。 XmlSerializer将尝试反序列化不以此格式的日期和时间字符串。为了更宽容，您需要创建一个字符串值的代理属性来反序列化日期。

由于您的日期字符串不是ISO 8601格式，因此它不包含时区信息。您需要从XML提供程序确定日期字符串的时区！（或者更好的是让它们以适当的格式生成日期和时间。）
您的<comment>元素有一个属性"value"，您没有反序列化：
```
<comment value="patiente">Exam completed for patience1</comment>
```
要捕获这个，您需要添加一个额外的类。

因此：

[Serializable, XmlRoot("patients")]
public class patients
{
    [XmlElement("patient")]
    public List<patient> patients_list { get; set; }
}

public class patient
{
    [XmlElement("firstname")]
    public string name { get; set; }

    [XmlElement("lastname")]
    public string surname { get; set; }

    [XmlElement("age")]
    public int age { get; set; }

    public string gender { get; set; }

    [XmlArray("exams")]
    [XmlArrayItem("exam")]
    public List<exam> exam { get; set; }
}

public class exam
{
    [XmlElement("id")]
    public int id { get; set; }

    [XmlIgnore]
    public DateTime date { get; set; }

    [XmlElement("date")]
    public string DateString
    {
        get
        {
            return XmlConvert.ToString(date, XmlDateTimeSerializationMode.Utc);
        }
        set
        {
            // You will need to check whether the dates and times in your XML file are in universal time or local time!
            date = DateTime.Parse(value, CultureInfo.InvariantCulture, DateTimeStyles.AssumeUniversal | DateTimeStyles.AdjustToUniversal);
        }
    }

    [XmlElement("comment")]
    public Comment comment { get; set; }
}

public class Comment
{
    [XmlAttribute("value")]
    public string Value { get; set; }

    [XmlText]
    public string CommentData { get; set; }
}

嵌套对象未在xml文件中序列化

1 个答案: