我有一些div应该出现在用户的滚动之后。所以我跟踪mouseScroll
事件。但我想为我的活动增加一些延迟。我尝试使用setTimeout
但它没有帮助......如果我完整滚动滚轮(每个动作不止一个),除了删除我的班级.shown
之外我什么也得不到。我该怎么办?这是我的代码:
$(document).ready(function() {
var timer;
var delay = 1000;
$(window).bind('mousewheel DOMMouseScroll', function(event) {
var shown = $(".shown").removeClass('shown');
timer = setTimeout(function() {
if (event.originalEvent.wheelDelta > 14 || event.originalEvent.detail < 14) {
// scroll up
if (shown.next() && shown.next().length) {
shown.next().addClass('shown');
} else {
shown.siblings(":first").addClass('shown');
}
} else {
// scroll down
if (shown.next() && shown.next().length) {
shown.next().addClass('shown');
} else {
shown.siblings(":first").addClass('shown');
}
}
}, delay);
}, function() {
clearTimeout(timer);
});
});
.view {
width: 300px;
height: 20px;
display: none;
clear: both;
transition: opacity 1s ease-out;
opacity: 0;
}
#first {
background: grey;
}
#second {
background: red;
}
#third {
background: blue;
}
#fourth {
background: orange;
}
#fifth {
background: green;
}
.view.shown {
display: block;
opacity: 1;
-webkit-animation: fadeIn 1s;
animation: fadeIn 1s;
}
@-webkit-keyframes fadeIn {
from {
opacity: 0;
}
to {
opacity: 1;
}
}
@keyframes fadeIn {
from {
opacity: 0;
}
to {
opacity: 1;
}
}
<div class="view shown" id="first"></div>
<div class="view" id="second"></div>
<div class="view" id="third"></div>
<div class="view" id="fourth"></div>
<div class="view" id="fifth"></div>
不幸的是,我也不知道如何以相同的延迟来反转这个脚本。任何帮助将不胜感激!
答案 0 :(得分:2)
尝试使用:
$(window).bind('mousewheel DOMMouseScroll', function(event) {
var shown = $(".shown").removeClass('shown');
clearTimeout(timer);
timer = setTimeout(function() {
if (event.originalEvent.wheelDelta > 14 || event.originalEvent.detail < 14) {
// scroll up
if (shown.next() && shown.next().length) {
shown.next().addClass('shown');
} else {
shown.siblings(":first").addClass('shown');
}
} else {
// scroll down
if (shown.next() && shown.next().length) {
shown.next().addClass('shown');
} else {
shown.siblings(":first").addClass('shown');
}
}
}, delay);
});