我有以下代码运行作为范围输入的figlet。 如何修改此代码以检查是否未指定b或e,将b设置为当前缓冲区的开头,以及当前缓冲区的结束?
(defun figlet-region (&optional b e)
(interactive "r")
(shell-command-on-region b e "/opt/local/bin/figlet" (current-buffer) t)
(comment-region (mark) (point)))
(global-set-key (kbd "C-c C-x") 'figlet-region)
肖恩帮助我得到了这个问题的答案
(defun figlet-region (&optional b e)
(interactive)
(let ((b (if mark-active (min (point) (mark)) (point-min)))
(e (if mark-active (max (point) (mark)) (point-max))))
(shell-command-on-region b e "/opt/local/bin/figlet" (current-buffer) t)
(comment-region (mark) (point))))
(global-set-key (kbd "C-c C-x") 'figlet-region)
答案 0 :(得分:7)
像这样:
(defun figlet-region (&optional b e)
(interactive "r")
(shell-command-on-region
(or b (point-min))
(or e (point-max))
"/opt/local/bin/figlet" (current-buffer) t)
(comment-region (mark) (point)))
但请注意,当此命令以交互方式运行时,将始终设置b
和e
。
你也可以这样做:
(require 'cl)
(defun* figlet-region (&optional (b (point-min)) (e (point-max)))
# your original function body here
)
编辑:
所以我猜你的意思是你希望能够以交互方式运行命令,即使该区域不活跃?那么也许这对你有用:
(defun figlet-region ()
(interactive)
(let ((b (if mark-active (min (point) (mark)) (point-min)))
(e (if mark-active (max (point) (mark)) (point-max))))
# ... rest of your original function body ...
))
答案 1 :(得分:3)
尝试
(unless b (setq b (point-min)))
(unless e (setq e (point-max)))