Question

我在SQL Server中有一个存储过程，用于检查今天的备份文件（文件名中包含日期的文件）。检查后，它会将robocopy这些文件转移到另一个文件夹。

挑战：在此文件夹中，可能存在昨天或其他日期的文件。但只有今天的bak文件才需要转移。

--@day allows me to capture the day of a month
declare @day char(2)
set @day = RIGHT('00' + CONVERT(NVARCHAR(2),DATEPART(DAY,GETDATE())),2)
--print @day

--In "MyFolder", it might containts files like 
--Project_backupfile_01_2006_02_28_001.bak
--OR Project_backupfile_01_2006_02_27_001.bak

--Currently I need to hard code 28 to represent 28th. How to pass in @day?
EXEC master..xp_cmdshell 'dir d:\myfolder\Project*28*.bak/b'

--Similarly, I would like to pass in @day variable so that the --Project_backupfile*02_*@day.bak

-- Copy the backup fules from ftp to a local drive
EXEC master..xp_cmdshell 'robocopy "d:\source" "E:\MSSQL\Restore\" Project_backupfile*_02_28*.bak /NFL /NDL /COPY:DAT /R:2 /W:1 /XO /E /Z /MT:10'

Answer 1

在将命令传递给xp_cmdshell

之前使用变量来形成命令

declare @cmd varchar(100)
select @cmd = 'dir d:\myfolder\Project*' + datename(day, getdate()) + '*.bak/b'
-- print @cmd
exec master..xp_cmdshell @cmd

注意：datename(day, getdate())会以字符串形式显示月中的某一天。

stuff(convert(varchar(5), getdate(), 101), 3, 1, '_')会给你02_28

将变量传递给xp_cmdshell

1 个答案: