Question

实际上这是一个字符串，

如何将其转换为对象或数组..

{"kind": "delivery_quote", "fee": 750, "created": "2016-02-28T19:13:38Z", "expires": "2016-02-28T19:18:38Z", "currency": "usd", "duration": 60, "dropoff_eta": "2016-02-28T20:18:38Z", "id": "dqt_KhC5sbjq00Jn6F"}

我试过这个

$array=explode(' ',$result);
$json = json_encode($result);
print($json);

它给我这样的结果

"{\"kind\": \"delivery_quote\", \"fee\": 750, \"created\": \"2016-02-28T19:13:38Z\", \"expires\": \"2016-02-28T19:18:38Z\", \"currency\": \"usd\", \"duration\": 60, \"dropoff_eta\": \"2016-02-28T20:18:38Z\", \"id\": \"dqt_KhC5sbjq00Jn6F\"}"

但我怎样才能正确地做到这一点，以便我可以像

那样取得结果

echo $json->fee;

这是迄今为止我所拥有的Eval。

帮助

Answer 1

您正在尝试对json进行编码。 json_encode返回值的JSON表示形式。如果要将json转换为数组，则应使用json_decode作为：

$result = '{"kind": "delivery_quote", "fee": 750, "created": "2016-02-28T19:13:38Z", "expires": "2016-02-28T19:18:38Z", "currency": "usd", "duration": 60, "dropoff_eta": "2016-02-28T20:18:38Z", "id": "dqt_KhC5sbjq00Jn6F"}';
$json = json_decode($result);
echo $json->fee;

将费用的值作为输出：

Answer 2

<?php
$result = '{"kind": "delivery_quote", "fee": 750, "created": "2016-02-28T19:13:38Z", "expires": "2016-02-28T19:18:38Z", "currency": "usd", "duration": 60, "dropoff_eta": "2016-02-28T20:18:38Z", "id": "dqt_KhC5sbjq00Jn6F"}';

var_dump(json_decode($result));
var_dump(json_decode($result, true));

字符串到数组或对象

2 个答案: