Question

这是一个视图（一个状态的templateUrl），并且isset由于某种原因剂量正常工作..我在代码的底部通过传入if（isset（$ _ POST [“submit”]））{do这个} 。但它做到了这一点。我清楚地给它一个名称属性“提交”和一个类型属性“提交”。请帮忙谢谢：

    <?php
var_dump($_GET);
require_once('PhpConsole.phar');
require_once('connection.php');
  ?>
<!DOCTYPE html>
<html lang="en-US">
<head>
</head>

<body>

    <div id="page">

    <h1>Registration </h1>
    <form  method = "post">
          <input  type = "text" name = "username" placeholder = "Username"required/>
          <br>
          <input  type = "text"name = "email" placeholder = "Email"required/>
          <br>
          <input type = "text" placeholder = "password" name = "password" required/>
          <br>
          <input type = "submit" name = "submit"/>
    </form>
    </div>
<?php
$username = $_POST["username"];
$email = $_POST["email"];
$password = $_POST["password"];
if(isset($_POST["submit"])){

  $query = "INSERT INTO authe (authe.Email , authe.Password, authe.Username) VALUES ('".$email."', '".$password."' , '".$username."')";
  if($result = $connection->query($query))
  {
  header("Location: http://localhost:8012/phpForm/login.php");
  }
  else{
    echo "Something Went wrong...";
  }
}
 ?>

</body>
  </html>

Answer 1

当我测试时，这个普通的PHP代码可以工作，

<!DOCTYPE html>
<html lang="en-US">
    <head>
    </head>
    <body>
        <div id="page">
            <h1>
                Registration 
            </h1>
            <form  method = "post">
                <input  type = "text" name = "username" placeholder = "Username"required/>
                <br>
                <input  type = "text"name = "email" placeholder = "Email"required/>
                <br>
                <input type = "text" placeholder = "password" name = "password" required/>
                <br>
                <input type = "submit" name = "submit"/>
            </form>
        </div>
        <?php
            print_r($_POST); 
            if(isset($_POST["username"])){
                $username = $_POST["username"];
            }
            if(isset($_POST["email"])){
                $email = $_POST["email"];
            }
            if(isset($_POST["password"])){
                $password = $_POST["password"];
            }
            if(isset($_POST["submit"])){
                    echo $username .PHP_EOL;
                    echo $email .PHP_EOL;
                    echo $password .PHP_EOL;
            }
        ?>
    </body>
</html>

现在，根据其他人的要求，请使用Angular组件发布非工作代码以进一步提供帮助。

Isset无法处理提交按钮

1 个答案: