我遇到了常见的“模型尚未加载”错误,该错误源于将单独的信号文件导入我的应用models.py
。我找到了2个关于如何创建AppConfig并在ready()函数中导入信号的简单指南,但我无法使其正常工作。我使用的是最常见的答案here以及this博文。
部分原因可能是因为我的整个项目都有一个名称funproj
,并且大部分代码所在的主应用程序被称为app
- 我是使用Visual Studio和Python Tools for VS,它在我创建项目时生成了这个结构。这是层次结构:
funproj
|--- __init__.py
|--- setttings.py
|--- urls.py
|
|--app
| |--- __init__.py
| |--- models.py
| |--- signals.py
|
|--otherapp
| |--- __init__.py
| |--- other stuff
这是缩写,但我已经尝试在apps.py
和__init.py__
下放置funproj
所需的app
和相关代码,但这两种方法都不起作用。这就是我对每一个人的看法:
apps.py
from django.apps import AppConfig
class FunProjAppConfig(AppConfig):
name = 'app'
def ready(self):
from app import signals
__ init.py__添加
#import signals in the app config
default_app_config = 'app.apps.FunProjAppConfig'
在app
中使用此代码对我来说更有意义,因为它包含需要加载的信号,但是我链接的示例对我来说并不清楚。一个人提到“app目录”,但我不确定这是否真的意味着app
,我认为它应该是,或者他们是否将app用作项目的同义词。
我认为这不会很难解决,我只是无法弄清楚我做错了什么。
编辑:这是使用Django 1.8的Python 3.4。下面的回溯,当我只有一个signals.py
文件并在那些信号的`models.py'中导入时,我得到了同样的错误。
C:\Python34\lib\importlib\_bootstrap.py:321: RemovedInDjango19Warning: The utili
ties in django.db.models.loading are deprecated in favor of the new application
loading system.
return f(*args, **kwds)
Traceback (most recent call last):
File "C:\Users\David\Source\Repos\path\to\projfiles\manage.py", line
17, in <module>
execute_from_command_line(sys.argv)
File "C:\Python34\lib\site-packages\django\core\management\__init__.py", line
338, in execute_from_command_line
utility.execute()
File "C:\Python34\lib\site-packages\django\core\management\__init__.py", line
312, in execute
django.setup()
File "C:\Python34\lib\site-packages\django\__init__.py", line 18, in setup
apps.populate(settings.INSTALLED_APPS)
File "C:\Python34\lib\site-packages\django\apps\registry.py", line 108, in pop
ulate
app_config.import_models(all_models)
File "C:\Python34\lib\site-packages\django\apps\config.py", line 198, in impor
t_models
self.models_module = import_module(models_module_name)
File "C:\Python34\lib\importlib\__init__.py", line 109, in import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 2254, in _gcd_import
File "<frozen importlib._bootstrap>", line 2237, in _find_and_load
File "<frozen importlib._bootstrap>", line 2226, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 1200, in _load_unlocked
File "<frozen importlib._bootstrap>", line 1129, in _exec
File "<frozen importlib._bootstrap>", line 1471, in exec_module
File "<frozen importlib._bootstrap>", line 321, in _call_with_frames_removed
File "C:\Users\David\Source\Repos\path\to\projfiles\app\models.py", l
ine 11, in <module>
from app import signals
File "C:\Users\David\Source\Repos\path\to\projfiles\app\signals.py",
line 7, in <module>
@receiver(post_save, sender=get_model('app', 'Game'))
File "C:\Python34\lib\site-packages\django\apps\registry.py", line 199, in get
_model
self.check_models_ready()
File "C:\Python34\lib\site-packages\django\apps\registry.py", line 131, in che
ck_models_ready
raise AppRegistryNotReady("Models aren't loaded yet.")
django.core.exceptions.AppRegistryNotReady: Models aren't loaded yet.
EDIT2:我在print
函数中添加了ready()
,但没有看到输出。以下是我安装的应用:
INSTALLED_APPS = (
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'kombu.transport.django',
'accounts',
'app',
'scores',
'rest_framework',
'rest_framework.authtoken',
'rest_auth',
# Uncomment the next line to enable the admin:
'django.contrib.admin',
# Uncomment the next line to enable admin documentation:
# 'django.contrib.admindocs',
)
答案 0 :(得分:5)
您似乎同时导入了/*Set Slim up*/
$container = new \Slim\Container();//Ver si le afecta o no los paréntesis ()
$container['settings'] = function($c){
return $c['config']->get('settings');
};
$container['config'] = function($c){ //c= current state of our container
return new \Noodlehaus\Config('../config/app.php');//We could pass more parameters ... as an array ['param1','param2','etc']
};
$container['view'] = function($c){//c= current state of our container
$view = new Slim\Views\Twig('../resources/views');//Ubicación de las vistas
//Ability to generate URLs to routes from within our views
$view->addExtension(new \Slim\Views\TwigExtension(
$c['router'],
$c['config']->get('url')
));
return $view;
};
//base de datos:
$container['db'] = function($c){
//return new PDO('mysql:host=127.0.0.1;dbname=destructy','root','root');
return new PDO(
'mysql:host='.$c['config']->get('db.mysql.host').';dbname='.$c['config']->get('db.mysql.dbname'),
$c['config']->get('db.mysql.username'),
$c['config']->get('db.mysql.password'));
};
$app = new Slim\App($container);
require_once 'routes.php';
和$app->get('/',function($request,$response,$args){
echo 'Destructy - Home.';
echo '<p style="color: darkblue">Welcome to the admin area</p>';
echo '<p>Testing access to config parameters ...</p>';
echo $this->config->get('db.mysql.host').'<br>';
echo $this->config->get('url');
/*Testing out DB connection*/
var_dump($this->db);
$this->view->render($response,'home.twig');
});
$app->run();
信号。加载apps.py
后会导入models.py
,然后尝试引用您的models.py
模型,导致“模型尚未加载”错误。
从signals
移除Game
。您可以从from app import signals
导入models.py
,但不能从另一端导入。
答案 1 :(得分:0)
试试这个:
@receiver(post_save, sender='app.Game')