Question

我有一个变量：

var value=[
{"0","0",650,"0","0",357,"0","0","0","0",200,"0",48,"0",3053,"0","0","0","0","0",45,50}
,{"0","0",299,101,"0",126,"0","0","0","0",630,"0","0",88,3157,"0","0","0","0","0",10,21}
,{"0","0",123,3030,"0",368,"0","0","0","0","0","0",76,-44,1967,"0","0","0","0","0",29,64}
,{"0","0",88,343,"0",320,"0","0","0","0","0","0",175,"0",336,"0","0","0","0","0",21,98}
,{"0","0",503,410,"0",1127,"0","0","0","0","0","0",77,87,1264,"0","0","0","0","0",5,128}
,{"0","0",1754,607,40,2565,"0","0","0","0","0","0",102,70,12506,"0","0","0","0","0",178,1966}
,{"0","0","0","0",60,153,"0","0","0","0","0","0","0","0","0","0","0","0","0","0",15,"0"}
]
var result= JSON.parse(value);

当我在javacript中将其解析为JSON时，会发生错误：

未捕获的SyntaxError：意外的令牌，

Answer 1

JSON中的对象用{}表示。对象具有键值对。例如：

{
    "foo": "bar",
    "example: "something",
    "key": "value"
}

JSON中的数组用[]表示。它们是数字，字符串，对象等的列表。例如：

[
    "foo",
    "bar",
    "something",
    "example"
]

您的问题是您使用{}作为数组。尝试将您的JSON更改为：

[
    ["0","0",650,"0","0",357,"0","0","0","0",200,"0",48,"0",3053,"0","0","0","0","0",45,50,["0","0",299,101,"0",126,"0","0","0","0",630,"0","0",88,3157,"0","0","0","0","0",10,21],["0","0",123,3030,"0",368,"0","0","0","0","0","0",76,-44,1967,"0","0","0","0","0",29,64],["0","0",88,343,"0",320,"0","0","0","0","0","0",175,"0",336,"0","0","0","0","0",21,98],["0","0",503,410,"0",1127,"0","0","0","0","0","0",77,87,1264,"0","0","0","0","0",5,128],["0","0",1754,607,40,2565,"0","0","0","0","0","0",102,70,12506,"0","0","0","0","0",178,1966],["0","0","0","0",60,153,"0","0","0","0","0","0","0","0","0","0","0","0","0","0",15,"0"]
]

此外，在JavaScript中，JSON是默认的Object Notation，因此除非您的JSON被表示为字符串，否则您不需要调用JSON.parse。

Answer 2

Javascript中的对象无法以这种方式呈现：

{"0","0",650,"0","0",357,"0","0","0","0",200,"0",48,"0",3053,"0","0","0","0","0",45,50}

对象呈现应具有以下格式：

{property_name : property_value, ... : ... , ... }

JSON.parse期待':'，但获得了','。

JSON Parse：Uncaught SyntaxError：意外的令牌，Javascript

2 个答案: