Question

这是我的休息控制器（服务器）：

@RestController
public class RemoteController {

    @RequestMapping(value="/test", method=RequestMethod.GET)  
    public Return serverTest(HttpServletRequest req, SearchFilter search) throws Exception{
        //...
        return new OutputTest();
    }
}

我想用SearchFilter对象作为输入为这个GET控制器编写相应的客户端。

public void clientTest(){
        SearchFilter input=new SearchFilter();
        RestTemplate restTemplate = new RestTemplate();
        HttpHeaders headers = new HttpHeaders();
        headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
        HttpEntity<String> entity = input;// how to store SearchFilter input ??????
        ResponseEntity<OutputTest> response=restTemplate.exchange("http://localhost:8080/test", HttpMethod.GET, entity, OutputTest.class);
        OutputTest out=response.getBody();
}

如何将单个对象发送到restTemplate？

Answer 1

您应该告诉Spring如何将请求参数绑定到SearchFilter。有多种方法可以实现这一点，最简单的解决方案是使用ModelAttribute注释：

@RequestMapping(value="/test", method=RequestMethod.GET)  
public Return serverTest(HttpServletRequest req, @ModelAttribute SearchFilter search) throws Exception{
    //...
    return new OutputTest();
}

假设您的SearchFilter看起来像这样：

public class SearchFilter {
    private String query;
    // other filters and getters and setters
}

如果您向/test?query=something发出请求，SearchFilter将填充已发送的查询参数。要使用RestTemplate发送此请求：

RestTemplate template = new RestTemplate();

// prepare headers
HttpHeaders headers = new HttpHeaders();
headers.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON));

// request without body, just headers
HttpEntity<Object> request = new HttpEntity<>(headers);

ResponseEntity<OutputTest> response = template.exchange("http://localhost:8080/test?query=something", 
            HttpMethod.GET, 
            request, 
            OutputTest.class);

我能想到的另一种方法是实现HandlerMethodArgumentResolver来解析SearchFilter个参数。此外，您可以将SearchFilter分开并使用多个RequestParam。

使用Spring RestTemplate和自定义Object输入参数来休息客户端

1 个答案: