计算匹配值

Question

当immediate_id与start_id匹配或者immediate_id与end_id匹配时，我想返回任何计数大于3的立即数.start_id将等于end_id并且计数大于3或者start_id将等于immediate_id并且计数大于3.现在返回该特定立即数的所有匹配，而不是立即返回大于3的匹配。 immediate有immediate_id，start有start_id，end有end_id，每个immediate有一个start和start_id有end和end_id。我只想要immediate_id = start_id＆gt;的情况3和immediate_id = end_id＆gt; 3。

select immediate
count(immediate) OVER (partition by start_id) as matchCount
from addresses where
start_id = end_id
or start_id = immediate_id
and year = 2016

Answer 1

您需要将or语句包装在括号中，并实际将> 3添加到您的where子句中，如下所示：

where count(immediate) > 3 and (immediate_id = start_id or immediate_id = end_id)