我想为以下选择创建一个代码对象:
var app = angular.module('mainApp', []);
app.controller('register', function ($scope, $http) {
$scope.send = function register() {
alert("test");
$http.post("http://52.77.16.197:8000/subscribe/", transformRequest = transformRequestAsFormPost, data = JSON.stringify({ email: $scope.email, role: $scope.role, home: $scope.home }))
.success(function (response) {
alert("hi");
$scope.persons = data;
}).error(function (response) {
if (response.message == "already_subscribed") {
alert("already_subscribed");
}
else {
alert("error");
}
});
}
});
angular.module('mainApp')
.factory("transformRequestAsFormPost",
function () {
function transformRequest(data, getHeaders) {
var serializeData = function (obj, result, keyName) {
if (typeof (keyName) === 'undefined') {
keyName = null;
}
var cloneObj = JSON.parse(JSON.stringify(obj));
$.each(cloneObj, function (idx, v) {
if (v instanceof Object) {
var newIdx = encodeURIComponent(idx);
var newKeyName = keyName === null ? newIdx : keyName + "[" + newIdx + "]";
serializeData(v, result, newKeyName);
}
else {
var key = encodeURIComponent(idx);
if (keyName !== null) {
key = keyName + "[" + key + "]";
}
result.push(
key + "=" + encodeURIComponent(v)
);
}
});
};
var result = [];
var headers = getHeaders();
headers["Content-type"] = "application/x-www-form-urlencoded; charset=utf-8";
serializeData(data, result);
return result.join("&");
}
return (transformRequest);
});
app.config(['$httpProvider', function ($httpProvider) {
$httpProvider.defaults.useXDomain = true;
//$httpProvider.defaults.withCredentials = true;
delete $httpProvider.defaults.headers.common["X-Requested-With"];
$httpProvider.defaults.headers.common["Accept"] = "application/json";
$httpProvider.defaults.headers.common["Content-Type"] = "application/json";
}
]);
function register() {
alert("submit");
var scope = angular.element(document.getElementById("reg")).scope();
scope.$apply(function () {
scope.send();
});
}
我试过了:
"LAND1"= 'Park / Recreation / Open Space' AND "LAND2"= 'Park / Recreation / Open Space'
这会出错。有没有办法保留LAND1和LAND2的双重qoutes?我如何在这方面使用格式?
答案 0 :(得分:2)
以下内容如何:
>>> code_string = """"LAND1"= 'Park / Recreation / Open Space' AND "LAND2"= 'Park / Recreation / Open Space'"""
>>> code_string
'"LAND1"= \'Park / Recreation / Open Space\' AND "LAND2"= \'Park / Recreation / Open Space\''
答案 1 :(得分:0)
如果Idos的回答不是你想要的,也许这是?
>>> string = "LAND1 = 'Park / Recreation / Open Space'; LAND2 = 'Park / Recreation / Open Space'"
>>> exec(string)
>>> LAND1
'Park / Recreation / Open Space'
>>> LAND2
'Park / Recreation / Open Space'
坚持一种报价。此外,由于你是exec
',因此exec
'd等号的左侧不能有引号,因为分配给字符串文字不会任何意义。