DimEmployee

Emp1，Emp2

DimCourse

课程1，课程2，课程3，课程4，课程5

FactPassedCourse
-----------------------------------------
(Emp1, Course1, DateKey1)
(Emp1, Course2, DateKey2)
(Emp1, Course2, DateKey3)
(Emp1, Course3, DateKey3)
(Emp1, Course4, DateKey3)
(Emp2, Course4, DateKey1)
(Emp2, Course5, DateKey5)

DimEmployee＆amp; DimCourse与我的Cube中的FactPassedCourse有规律的关系。

我希望根据每门课程获得员工人数，但如果员工不止一次通过特殊课程（如Course2），那么员工必须被计算一次，我的意思是我想要的结果：

MDX结果：

(Coursename: Course1    Employee_Count: 1)
(Coursename: Course2    Employee_Count: 1:because ONE employee passed this course two times)
(Coursename: Course3    Employee_Count: 1)
(Coursename: Course4    Employee_Count: 2: because two different employees passed this course)
(Coursename: Course5    Employee_Count: 1)

为了得到这个结果，我写了这个mdx查询，这会返回正确的结果，但这个查询的性能非常慢。

With 
  Member [measures].[Employee_Count] as 
     Count(
        Filter(
          [DimEmployee].EmployeeKey].members-[DimEmployee].[EmployeeKey].[All]),
          [measures].[FactPassedCourseCount]>0)
        )
  Set [Course_Set] as 
     Filter(
       ([DimCourse].[CourseKey].members–[DimCourse].CourseKey].[All]),
        [measures].[FactPassedCourseCount] > 0
     )
Select 
   [measures].[Employee_Count] on 0
 , [Course_Set] on 1 
From MyCube

此查询结果为：

(Coursename: Course1    Employee_Count: 1)
(Coursename: Course2    Employee_Count)
(Coursename: Course3    Employee_Count: 1)
(Coursename: Course4    Employee_Count)
(Coursename: Course5    Employee_Count: 1)

有没有更好的方法来编写具有快速性能的mdx查询？

Answer 1

这样更快吗？

With 
  Member [measures].[Employee_Count] as 
     Count(
        EXISTING 
           NONEMPTY(
             [DimEmployee].[EmployeeKey].[EmployeeKey]
            ,[measures].[FactPassedCourseCount]
           )
        )
Select 
   [measures].[Employee_Count] on 0
 , NONEMPTY(
      [DimCourse].[CourseKey].[CourseKey]
     ,[measures].[FactPassedCourseCount]
   ) on 1 
From [MyCube];

Answer 2

接受答案的替代方案 -

with member [measures].[Employee_Count] AS
NonEmpty
    (
     [DimEmployee].EmployeeKey].[EmployeeKey].members,
     ([DimCourse].[CourseKey].Currentmember, [measures].[FactPassedCourseCount])
    ).Count


Select 
   [measures].[Employee_Count] on 0
 , [Course_Set] on 1 
From MyCube

此外，如果您想根据任何值进行过滤，有一种方法可以在不使用filter的情况下进行过滤。

with
member measures.GrtThan5 as
IIF(
    [Measures].[Claim As Of - Count] > 5,
    1,
    NULL
   )

定义必须改为以下 -

member [measures].[Employee_Count] AS
NonEmpty
    (
     [DimEmployee].EmployeeKey].[EmployeeKey].members,
     ([DimCourse].[CourseKey].Currentmember, [measures].GrtThan5)
    ).Count

在mdx中模拟分组

DimEmployee

DimCourse

2 个答案: