请告诉我,当我打开时,如何将照片插入for j,i in enumerate(files):
if name in i:
print i
fn,_,sn = i.rpartition(name)
os.rename(os.path.join(path, i), os.path.join(path, fn+sn))
files[j] = fn+sn
for j,i in enumerate(dir):
if name in i:
print i
fn,_,sn = i.rpartition(name)
os.rename(os.path.join(path, i), os.path.join(path, fn+sn))
dir[j] = fn+sn
<img>
并选择任何文件?
我如何使用JS / JQuery?
答案 0 :(得分:0)
使用&#39; FileReader&#39;对象:
$("#yourinput").change(function () {
var file = this.files[0];
var reader = new FileReader();
reader.onload = function (e) {
$("#yourimg").attr("src", e.target.result);
}
reader.readAsDataURL(file);
});