Question

我有this regex：

/(\[.*?\])/g

现在我想更改该正则表达式以匹配除current-matches之外的所有内容。我怎么能这样做？

例如：

当前正则表达式：

   here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here

//                   ^^^^^^^^^^^^^^^^^^^^^^^^^^^                 ^^^^^^^^^^^^^^^^^^^^^

我想要这个：

   here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here
// ^^^^^^^^^^^^^^^^^^                           ^^^^^^^^^^^^^^^^^                     ^^^^^^^^^

Answer 1

匹配内部的内容或捕获^{the trick}

之外的内容

\[.*?\]|([^[]+)

See demo at regex101

<强>演示：

var str = 'here is some text [anything123][/21something] and here is too [sometext][/afewtext] and here';

var regex = /\[.*?\]|([^[]+)/g;
var res = '';

// Do this until there is a match
while(m = regex.exec(str)) {
    // If first captured group present
    if(m[1]) {
        // Append match to the result string
        res += m[1];
    }
}

console.log(res);
document.body.innerHTML = res; // For DEMO purpose only

如何匹配除匹配值以外的所有内容？

1 个答案: