Question

我正在尝试在我的表格中创建一个新的

JS：

function addElement() {

    var message = document.getElementById('inputsend');
    var now = new Date();

    var table = document.getElementById('messagebox');

    var tr = document.createElement('tr');

    var tdTime = document.createElement('td');
    tdTime.innerHTML = now.getHours() +":"+now.getMinutes() + " ";

    var tdName = document.createElement('td');
    tdName = userName + " ";

    var tdMessage = document.createElement('td');
    tdMessage = message;

    tr.appendChild(tdTime);
    tr.appendChild(tdName);
    tr.appendChild(tdMessage);

    table.appendChild(tr);

    document.getElementById('inputsend').value = "";

}

HTML：

<table id="messagebox">
</table>

但它不起作用，并且chrome说无法在节点上执行appendchild

Answer 1

.innerHTML＆amp; tdName中缺少tdMessage appendChild，因此您将字符串传递给无法处理的var tdName = document.createElement('td'); tdName.innerHTML = userName + " "; var tdMessage = document.createElement('td'); tdMessage.innerHTML = message;。

$regex_ipv4 = '((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\\d])';
$regex_integer = '(\\d+)';

$x = "123.123.123.123";
$x2 = $x . ":12345";

preg_match("/^(?<ipv4>".$regex_ipv4.")(:)(?<port>".$regex_integer.")$/is", $x, $matches1);
preg_match("/^(?<ipv4>".$regex_ipv4.")(:)(?<port>".$regex_integer.")$/is", $x2, $matches2);

print_r($matches1);
print_r($matches2);

无法在节点上执行appendchild

1 个答案: