Question

我正在尝试从Spring引导休息服务下载文件。

@RequestMapping(path="/downloadFile",method=RequestMethod.GET)
    @Consumes(MediaType.APPLICATION_JSON_VALUE)
    public  ResponseEntity<InputStreamReader> downloadDocument(
                String acquistionId,
                String fileType,
                Integer expressVfId) throws IOException {
        File file2Upload = new File("C:\\Users\\admin\\Desktop\\bkp\\1.rtf");
        HttpHeaders headers = new HttpHeaders();
        headers.add("Cache-Control", "no-cache, no-store, must-revalidate");
        headers.add("Pragma", "no-cache");
        headers.add("Expires", "0");
        InputStreamReader i = new InputStreamReader(new FileInputStream(file2Upload));
        System.out.println("The length of the file is : "+file2Upload.length());

        return ResponseEntity.ok().headers(headers).contentLength(file2Upload.length())
                .contentType(MediaType.parseMediaType("application/octet-stream"))
                .body(i);
        }

当我尝试从浏览器下载文件时，它会开始下载，但始终会失败。导致下载失败的服务有什么问题吗？

Answer 1

使用InputStreamResource

选项1

给定Resource的
InputStream实施。

只有在没有其他特定资源实施的情况下才能使用
适用。特别是，在可能的情况下，更喜欢ByteArrayResource或任何基于文件的资源实现。

@RequestMapping(path = "/download", method = RequestMethod.GET)
public ResponseEntity<Resource> download(String param) throws IOException {

    // ...

    InputStreamResource resource = new InputStreamResource(new FileInputStream(file));

    return ResponseEntity.ok()
            .headers(headers)
            .contentLength(file.length())
            .contentType(MediaType.parseMediaType("application/octet-stream"))
            .body(resource);
}

Option2 作为InputStreamResource的文档建议 - 使用ByteArrayResource：

@RequestMapping(path = "/download", method = RequestMethod.GET)
public ResponseEntity<Resource> download(String param) throws IOException {

    // ...

    Path path = Paths.get(file.getAbsolutePath());
    ByteArrayResource resource = new ByteArrayResource(Files.readAllBytes(path));

    return ResponseEntity.ok()
            .headers(headers)
            .contentLength(file.length())
            .contentType(MediaType.parseMediaType("application/octet-stream"))
            .body(resource);
}

Answer 2

我建议使用 StreamingResponseBody ，因为有了它，应用程序可以直接写入响应（OutputStream），而无需占用Servlet容器线程。如果要下载很大的文件，这是个好方法。

@GetMapping("download")
public StreamingResponseBody downloadFile(HttpServletResponse response, @PathVariable Long fileId) {

    FileInfo fileInfo = fileService.findFileInfo(fileId);
    response.setContentType(fileInfo.getContentType());
    response.setHeader(
        HttpHeaders.CONTENT_DISPOSITION, "attachment;filename=\"" + fileInfo.getFilename() + "\"");

    return outputStream -> {
        int bytesRead;
        byte[] buffer = new byte[BUFFER_SIZE];
        InputStream inputStream = fileInfo.getInputStream();
        while ((bytesRead = inputStream.read(buffer)) != -1) {
            outputStream.write(buffer, 0, bytesRead);
        }
    };
}

Ps .：使用 StreamingResponseBody 时，强烈建议配置Spring MVC中使用的TaskExecutor来执行异步请求。 TaskExecutor是一个接口，用于抽象Runnable的执行。

更多信息：https://medium.com/swlh/streaming-data-with-spring-boot-restful-web-service-87522511c071

Answer 3

下面的示例代码对我有用，可能会对某人有所帮助。

import org.springframework.core.io.ByteArrayResource;
import org.springframework.core.io.Resource;
import org.springframework.http.HttpHeaders;
import org.springframework.http.MediaType;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;

import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

@RestController
@RequestMapping("/app")
public class ImageResource {

    private static final String EXTENSION = ".jpg";
    private static final String SERVER_LOCATION = "/server/images";

    @RequestMapping(path = "/download", method = RequestMethod.GET)
    public ResponseEntity<Resource> download(@RequestParam("image") String image) throws IOException {
        File file = new File(SERVER_LOCATION + File.separator + image + EXTENSION);

        HttpHeaders header = new HttpHeaders();
        header.add(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=img.jpg");
        header.add("Cache-Control", "no-cache, no-store, must-revalidate");
        header.add("Pragma", "no-cache");
        header.add("Expires", "0");

        Path path = Paths.get(file.getAbsolutePath());
        ByteArrayResource resource = new ByteArrayResource(Files.readAllBytes(path));

        return ResponseEntity.ok()
                .headers(header)
                .contentLength(file.length())
                .contentType(MediaType.parseMediaType("application/octet-stream"))
                .body(resource);
    }

}

Answer 4

我想分享一种使用JavaScript（ES6），反应和 Spring Boot 后端下载文件的简单方法：

Spring boot Rest Controller

来自org.springframework.core.io.Resource的资源

    @SneakyThrows
    @GetMapping("/files/{filename:.+}/{extraVariable}")
    @ResponseBody
    public ResponseEntity<Resource> serveFile(@PathVariable String filename, @PathVariable String extraVariable) {

        Resource file = storageService.loadAsResource(filename, extraVariable);
        return ResponseEntity.ok()
               .header(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=\"" + file.getFilename() + "\"")
               .body(file);
    }

使用AXIOS 反应

将responseType设置为arraybuffer，以指定响应中包含的数据类型。

export const DownloadFile = (filename, extraVariable) => {
let url = 'http://localhost:8080/files/' + filename + '/' + extraVariable;
return axios.get(url, { responseType: 'arraybuffer' }).then((response) => {
    return response;
})};

最后一步> 下载
借助js-file-download，您可以触发浏览器将数据保存到文件中，就像下载文件一样。

DownloadFile('filename.extension', 'extraVariable').then(
(response) => {
    fileDownload(response.data, filename);
}
, (error) => {
    // ERROR 
});

Answer 5

如果您需要从服务器的文件系统下载巨大的文件，则 ByteArrayResource 可以占用所有Java堆空间。在这种情况下，您可以使用FileSystemResource

Answer 6

    @GetMapping("/downloadfile/{productId}/{fileName}")
public ResponseEntity<Resource> downloadFile(@PathVariable(value = "productId") String productId,
        @PathVariable String fileName, HttpServletRequest request) {
    // Load file as Resource
    Resource resource;

    String fileBasePath = "C:\\Users\\v_fzhang\\mobileid\\src\\main\\resources\\data\\Filesdown\\" + productId
            + "\\";
    Path path = Paths.get(fileBasePath + fileName);
    try {
        resource = new UrlResource(path.toUri());
    } catch (MalformedURLException e) {
        e.printStackTrace();
        return null;
    }

    // Try to determine file's content type
    String contentType = null;
    try {
        contentType = request.getServletContext().getMimeType(resource.getFile().getAbsolutePath());
    } catch (IOException ex) {
        System.out.println("Could not determine file type.");
    }

    // Fallback to the default content type if type could not be determined
    if (contentType == null) {
        contentType = "application/octet-stream";
    }

    return ResponseEntity.ok().contentType(MediaType.parseMediaType(contentType))
            .header(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=\"" + resource.getFilename() + "\"")
            .body(resource);
}

要测试它，请使用邮递员

http://localhost:8080/api/downloadfile/GDD/1.zip

Answer 7

使用Apache IO可能是复制流的另一种选择

@RequestMapping(path = "/file/{fileId}", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<?> downloadFile(@PathVariable(value="fileId") String fileId,HttpServletResponse response) throws Exception {

    InputStream yourInputStream = ...
    IOUtils.copy(yourInputStream, response.getOutputStream());
    response.flushBuffer();
    return ResponseEntity.ok().build();
}

maven依赖

    <dependency>
        <groupId>org.apache.commons</groupId>
        <artifactId>commons-io</artifactId>
        <version>1.3.2</version>
    </dependency>

从Spring启动休息服务下载文件

7 个答案: