如何读取动态字符串并将每个键字符串值存储到变量中？

Question

这是我的动态字符串：

String a= "SourceFilePath:C:\Users\Anuj\Desktop\Anuj Tamrakar Working Folder, BackUpFilePath:C:\Users\Anuj\Desktop\installer, SyncPath:C:\Users\Anuj\Desktop\PSI, Password:3SMpUGoJpIJdWwRDXau+OQ==, NumberOfTimes:2, Time0:10:10 AM, Time1:10:10 PM"

我需要读取字符串的内容，并且需要将每个键及其coressponding值存储到变量中。我需要像

这样的输出

var SourceFilePath = "C:\Users\Anuj\Desktop\Anuj Tamrakar Working Folder";
var BackUpFilePath="C:\Users\Anuj\Desktop\installer"
var SyncPath="C:\Users\Anuj\Desktop\PSI"
var Password="3SMpUGoJpIJdWwRDXau+OQ=="
var NumberOfTimes=2
var Time0=10:10 AM
var Time1=10:10 PM

这部分是动态的：

var NumberOfTimes:2
var Time0:10:10 AM
var Time1:10:10 PM

如果我的字符串文件中有NumberOfTimes:4。我会有4个时间值，即Time0，Time1，Time2和Time3。所以我需要将这4个时间值存储到4个变量中

Answer 1

您可以使用字典对象。

拆分字符串输入，然后循环遍历变量键值对：。 将密钥和值存储在字典中。

您不需要声明每个变量，但您可以通过键在字典中查找。

Answer 2

必须是下面的内容。

  // you can also fill an array dynamically
 var NumberOfTimes=["10:10 AM","10:11 AM","10:12 AM"]
 //count of stored items in array
 NumberOfTimes.length
 //in order to print or use in some where else
 NumberOfTimes.forEach(function(e,i){
 //do somethings
 });

Answer 3

我在控制台应用中尝试了这个并且工作正常。以下是我的解决方案。

static void Main(string[] args)
    {

        String a = @"SourceFilePath:C:\Users\Anuj\Desktop\Anuj Tamrakar Working Folder, BackUpFilePath:C:\Users\Anuj\Desktop\installer, SyncPath:C:\Users\Anuj\Desktop\PSI, Password:3SMpUGoJpIJdWwRDXau+OQ==, NumberOfTimes:2, Time0:10:10 AM, Time1:10:10 PM";

        Dictionary<string, string> processedString = ProcessString(a);

        //Here you can set the values to variable accessing it from the Dictionary
        var SourceFilePath = processedString["SourceFilePath"];
        var BackUpFilePath = processedString["BackUpFilePath"];
        var SyncPath = processedString["SyncPath"];
        var Password = processedString["Password"];
        var NumberOfTimes = Convert.ToInt32(processedString["NumberOfTimes"]);

        // And for the dynamic variables like Time01, Time02 I recommend you to create a list which holds all the time components.
        // Because creating a variable on the fly will be more complex for your requirement and is not necessary at this moment.
        //So you can do this
        var TimeComponents = processedString.Where(x => x.Key.StartsWith("Time")).Select(x => x).ToList();
        Console.ReadLine();
    }

分割字符串和创建字典的过程如下所示。

public static Dictionary<string, string> ProcessString(string toProcess)
    {
        Dictionary<string, string> processedString = new Dictionary<string, string>();
        var eachSubString = toProcess.Split(',');

        foreach (var subStr in eachSubString)
        {
            var keyValue = subStr.Trim().Split(new char[] { ':' }, 2);
            processedString.Add(keyValue[0], keyValue[1]);
        }

        return processedString;
    }

这是调试器的屏幕截图

如果有帮助，请告诉我。