Question

该程序将向用户显示程序的开始时间，结束时间和经过时间。例如，如果程序在09:23:45开始并在09:23:55结束，那么输出到用户就是这样，开始时间：09h：23m：45s结束时间：09h：23m：55s经过时间00h ：00米：10秒。我有问题会显示时间...... 请帮忙

这是主要的

import java.util.concurrent.TimeUnit;
import java.text.SimpleDateFormat;
public class ElapsedTimeWatch {

public static void main(String... args) throws InterruptedException {

    TimeWatch watch = TimeWatch.start();
    SimpleDateFormat dateFormat = new SimpleDateFormat("HH'h':mm'm':ss's'");
    System.out.println("Start Time is : " + dateFormat.format(timestart));
     String.format("%02dh:%02dm:%02ds",
                    TimeUnit.MILLISECONDS.toHours(watch.timestart()),//dateFormat.format(start)
                    TimeUnit.MILLISECONDS.toSeconds(watch.timestart()) -
                            TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(watch.timestart())));









    Thread.sleep(1000 * 10);



    System.out.println("End Time is : " + dateFormat.format(timeend));
     String.format("%02dh:%02dm:%02ds",
                    TimeUnit.MILLISECONDS.toHours(watch.timeend()),
                    TimeUnit.MILLISECONDS.toSeconds(watch.timeend()) -
                            TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(watch.timeend())));









    System.out.println("Elapsed Time custom format: " + watch.toMinuteSeconds());



}
}

时间表类

import java.util.concurrent.TimeUnit;

public class TimeWatch {

long starts;



private TimeWatch() {
    reset();
}

public static TimeWatch start() {
    return new TimeWatch();
}

public TimeWatch reset() {
    starts = System.currentTimeMillis();
    return this;
}




 public long time() {
    long ends = System.currentTimeMillis();
    return ends - starts;
}

//Start Time
public long timestart() {
   starts = System.currentTimeMillis();
    return starts;
}
//End Time
public long timeend() {
    long ends = System.currentTimeMillis();
    return ends;
}





public long time(TimeUnit unit) {
    return unit.convert(time(), TimeUnit.MILLISECONDS);


public String toMinuteSeconds(){
    return String.format("%d min, %d sec", time(TimeUnit.MINUTES),
            time(TimeUnit.SECONDS) - time(TimeUnit.MINUTES));
}




 }

Answer 1

根据oracle documentation，System.nanoTime（）与时钟无关。因此，在这种情况下，我们可以使用System.currentTimeMillis();来启动计时器。一旦计时器停止，我们可以使用以下代码打印失效：

public static void main(String[] args) throws InterruptedException {
    long start = System.currentTimeMillis();
    SimpleDateFormat dateFormat = new SimpleDateFormat("HH'h':mm'm':ss's'");
    Thread.sleep(10000);
    long end = System.currentTimeMillis();
    long difference = end - start;
    System.out.println("Start :" + dateFormat.format(start) );
    System.out.println("End :" + dateFormat.format(end) );
    String format = String.format("%d min, %d sec", 
            TimeUnit.MILLISECONDS.toMinutes(difference),
            TimeUnit.MILLISECONDS.toSeconds(difference) - 
            TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(difference))
        );
    System.out.println(format);
}

计算出现时间

1 个答案: