我有一个像以下的网络服务:
@Controller
@RequestMapping("/")
public class ApplicationController {
@RequestMapping(value="/Changes", method = RequestMethod.GET)
public String inspect(ModelMap model) {
model.addAttribute("msg", "example");
return "index";
}
}
链接中的:"localhost:8081/ChangesPDF/Changes?..."
我试图通过链接中的Alfresco获取此Web服务的响应:"localhost:8080/share"
。我现在有不同的端口(当我有相同的端口,这很好用),因此,使用不同的端口我在Alfresco中得到错误:
阻止跨源请求:同源策略禁止读取 http://localhost:8081/ChangesPDF/Changes处的远程资源?...(原因:标题CORS' Access-Control-Allow-Origin'缺失)。
如何添加此标题?
答案 0 :(得分:1)
您应该添加一个过滤器来设置" Access-Control-Allow-Origin"接受域" localhost:8081" (*为所有人)。
很可能您会在cores-filter-not-working
找到答案更多解释:
首先创建一个过滤器类
public class CorsFilter implements Filter {
private static final Logger log = Logger.getAnonymousLogger();
@Override
public void init(FilterConfig filterConfig) throws ServletException {}
@Override
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
HttpServletResponse response = (HttpServletResponse) servletResponse;
HttpServletRequest request = (HttpServletRequest) servletRequest;
// can be moved to properties
String[] allowDomain = {"localhost:8080","localhost:8081"};
String originHeader = request.getHeader("host");
for(String domian : allowDomain){
if(originHeader.endsWith(domian))
response.setHeader("Access-Control-Allow-Origin", originHeader);
break;
}
filterChain.doFilter(servletRequest, servletResponse);
}
@Override
public void destroy() {}
}
将映射添加到web.xml类
<filter>
<filter-name>cors</filter-name>
<filter-class>full name of your filter class here</filter-class>
</filter>
<filter-mapping>
<filter-name>cors</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
您应该根据您的要求在web.xml配置中定义URL pattren
答案 1 :(得分:1)
如果您使用的是Spring 4.2+,则可以使用@CrossOrigin注释:
@Controller
@RequestMapping("/")
public class ApplicationController {
@CrossOrigin
@RequestMapping(value="/Changes", method = RequestMethod.GET)
public String inspect(ModelMap model) {
model.addAttribute("msg", "example");
return "index";
}
}
否则,您需要在Spring应用程序中注册CORS过滤器。类似于this。
答案 2 :(得分:0)
我认为您的代码可能需要使用Spring的@CrossOrigin
注释,例如 :
import org.springframework.web.bind.annotation.CrossOrigin;
....
@Controller
@RequestMapping("/")
public class ApplicationController {
@CrossOrigin
@RequestMapping(value="/Changes", method = RequestMethod.GET)
public String inspect(ModelMap model) {
model.addAttribute("msg", "example");
return "index";
}
}
这将允许所有来源,这可能会或可能不足以满足您的需求。
作为参考,我在this article中找到了上述内容,并在Spring blog here中提及。
希望这有帮助!