Question

我有“单词”这个表：

id
name

insert into words values(null, 'one');
insert into words values(null, 'two');
insert into words values(null, 'three');

我需要清楚地找出整个桌子上使用的字母。在这种情况下，结果将是：

o
n
e
t
w
h
r

我实际上并不知道如何做到这一点。我发现了一些似乎可以解决它的存储过程。对所有行进行某种迭代，其中将新字母添加到最终结果中。有没有办法用纯sql命令执行此操作？

Answer 1

您可以将SUBSTRING与派生计数表一起使用：

SELECT DISTINCT SUBSTRING(word, n, 1) AS letter
FROM words w
CROSS JOIN 
(
   SELECT a.N + b.N * 10 + c.N * 1000 + 1 n
     FROM 
    (SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
   ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
   ,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) c
) n
WHERE n <= LENGTH(w.word)
ORDER BY letter;

的 SqlFiddleDemo

如果您需要o和O作为不同的字母添加COLLATE utf8_bin：

SELECT DISTINCT SUBSTRING(word, n, 1) COLLATE utf8_bin AS letter

MySQL查询以获取跨行使用的所有不同字母

1 个答案: